[英]Criteria Using the sessions ID to display infomation relevant
我正在寻找使用会话用户ID = PhysioReference(表中的字段)的条件,但它似乎不起作用? 什么是正确的方法或有更好的方法?
它可以将信息显示在表格中,但仅向登录的人分配该信息的位置
$sql="SELECT * FROM IA WHERE IASubmitted= 'no' AND PhysioReference = $_SESSION['SESS_MEMBER_ID']";
想要的文字表示形式( 不好的主意 )将在字符串变量语法中使用Complex(卷曲) :
$sql="SELECT * FROM IA
WHERE IASubmitted= 'no' AND PhysioReference = ${_SESSION['SESS_MEMBER_ID']}";
$sql="SELECT * FROM IA
WHERE IASubmitted= 'no' AND PhysioReference = ?";
/* Prepared statement, stage 1: prepare */
if (!($stmt = $mysqli->prepare("INSERT INTO test(id) VALUES (?)"))) {
echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
}
/* Prepared statement, stage 2: bind and execute */
if (!$stmt->bind_param("i", $_SESSION['SESS_MEMBER_ID'] )) {
echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
}
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
$ sql =“ SELECT * FROM IA tb1,成员tb2,其中tb1.PhysioReference = tb2.member_id和tb2.member_id =”。$ _ SESSION ['SESS_MEMBER_ID']; $结果= mysql_query($ SQL);
最终成功了
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