sql查询和分组依据

Question

我不确定这是否可行我不知道这是我的表：tbchecked

[id] [name] [status]

001   john     present
001   john     present
001   john     absent
001   john     absent
001   john     leave
001   john     present
001   john     present
002   ace      present
002   ace      absent
002   ace      leave

...

有可能的？ 在gridview1中输出如何查询？ 1-7 不在一周内，我想从 1 数到 xxx

[id] [name] [1]      [2]      [3]     [4]             [5]            [6]      [7]

001   john  present  present  absent  absent         leave          present  present
002   ace   present  absent   leave   ...

Answer 1

你可以试试这样的

DECLARE @TABLE TABLE
(  
ID INT,  
STATUS VARCHAR(10)
)

INSERT INTO @TABLE  
VALUES  (1, 'present'),
        (1, 'present'),
        (1, 'absent'),
        (1, 'absent'),
        (1, 'leave'),
        (1, 'present'),
        (1, 'present'),
        (2, 'present'),
        (2, 'absent'),
        (2, 'leave')


SELECT T1.ID,  
        STUFF(  
        (  
        SELECT ',' + T2.STATUS  
        FROM @TABLE T2  
        WHERE T1.ID = T2.ID  
        FOR XML PATH ('')  
        ),1,1,'')  
FROM @TABLE T1  
GROUP BY T1.ID

否则你可以使用游标来执行一个循环Declare Cursor

Answer 2

如果一个 ID 只有七行，那么这可能很有用。 如果 ID 是任何随机计数，那么您必须尽可能使用动态 sql 或过程。

select ID,

SUBSTRING_INDEX(status,',','1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','2'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','3'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','4'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','5'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','6'),',','-1'),

SUBSTRING_INDEX(SUBSTRING_INDEX(status,',','7'),',','-1')

 from
(

SELECT  ID, group_concat(status) as status  

FROM TABLE T

GROUP BY ID

) A