[英]Disable delete button if record exist in multiple table
我在这里用删除按钮在html表中显示mysql记录。 我需要做的是如果两个数据库表中都存在记录,则禁用删除按钮。
如果两个表中都已存在记录,如何禁用每行的删除按钮? 任何帮助将不胜感激。
$search = $mysqli1->real_escape_string($_POST['bid']);
$search = preg_replace("/[^A-Za-z0-9 ]/", '', $search);
$search = $_POST['bid'];
$res = $mysqli1->query("select * from code WHERE item LIKE '%$search%' OR item_code LIKE '%$search%' OR cat_code LIKE '%$search%' order by item_code ASC");
while($r = $res->fetch_assoc()){
echo "<tr>
<td><a href='#' id='".$r['id']."' class='del'><img src='../images/del.png'></a></td>
</tr>";
}
抛出一个简单的if()语句与pdo中的两个查询相关联,您可以在mysqli中使用-> rowCount()
所以你需要这个逻辑
query1 =表1中的计数行
query2 =表2中的计数行
就像您说它在两个表中都存在一样,应该将其隐藏,以便使用if-or statement
if(query1 == 0 || query2 == 0){
//show your button
}
这里的意思很简单:
if(query1 equals 0 rows OR query2 equals 0 rows){
//show your button
}
//While you don't put up the else with something else it won't show anything
//so if there are the value of 1+ rows in both query1 and query2 this won't show anything
如果您要我提供pdo示例,请回复
编辑:
PDO类使连接更容易
class Database extends PDO
{
private $db;
public function Database($host, $user, $pass, $db) {
try {
$this->db = new PDO("mysql:dbname=".$db.";host=".$host.";", $user, $pass);
} catch(PDOEXCEPTION $e) {
die('An error has occurred! [Code: '.$e->getCode().']! <br/>More info: ['.$e->getMessage().']!');
}
}
public function runQuery($query) {
try{
return $this->db->query($query);
} catch(PDOEXCEPTION $e) {
die('An error has occurred! [Code: '.$e->getCode().']!<br/>More info: ['.$e->getMessage().']!');
}
}
}
现在行计数: 更新了&&和2x query1检查,出现了一些错误
$consite = new Database('DBHost','DBUsername','DBPassword','DBName');
$query1 = $consite->runQuery("SELECT * FROM TABLE1");
$query2 = $consite->runQuery("SELECT * FROM TABLE2");
if($query1->rowCount() == 0 || $query2->rowCount() == 0) {
//do your while statement to loop through it
//if you done your while statement it only shows the delete button
//for items that are NOT in both tables
}
抱歉,我懒得添加while语句;)如果我是正确的,则可以从sql查询中的多个表中进行检查,因此,如果在1个查询之后进行多重检查,则可以使用1个查询来进行检查!
编辑:此问题的逻辑步骤:
1) Connect
database
2) query
table1
3) Count
table1
的entries
( records
)
4) query
table2
5) Count
table2
的entries
( records
)
6) Check
one
是否等于0
7)如果one
之一等于0
entries
( records
( rows
)),则显示按钮
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