[英]getting the multiple max row using group by and having clause
mysql> select * from raj;
+------+----------+
| id | quantity |
+------+----------+
| 1 | 250 |
| 1 | 250 |
| 2 | 250 |
| 2 | 150 |
| 3 | 150 |
| 3 | 150 |
| 4 | 150 |
| 4 | 350 |
+------+----------+
8 rows in set (0.00 sec)
mysql> select id,sum(quantity)
-> from raj
-> group by(id);
问题:从上表我想得到最大数量customer_id和quant输出应该是这样的
+------+---------------+
| id | sum(quantity) |
+------+---------------+
| 1 | 500 |
|
| 4 | 500 |
+------+---------------+
我尝试过的:
select id,sum(quantity) quant
from raj
group by(id)
having max(quant);
但上面的查询给出了空集。 我做错了什么?
您可以使用另一个查询来获取最大值,然后使用HAVING
子句匹配第一个查询的最大总和,因此如果有多个客户具有相同的最大数量,查询将返回所有客户
SELECT id,
SUM(quantity) quant,t.max_sum
from Table1
JOIN (SELECT SUM(quantity) max_sum
FROM Table1
GROUP BY id
ORDER BY max_sum DESC LIMIT 1) t
GROUP BY id
HAVING quant = t.max_sum
select groups.*
from
(select id,sum(quantity) quant
from raj
group by(id)) groups JOIN
(select max(quant) as max_q
from (select id,sum(quantity) quant
from raj
group by(id)) tmp
) max_data ON groups.quant=max_data.max_q
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