SQLSTATE [HY093]：错误，但我不明白为什么

Question

所以这是代码：try {

        $db->beginTransaction();
        $ipaddress = getenv('REMOTE_ADDR');
        $stmt2 = $db->prepare("INSERT INTO members (username, email, password, signup_date, ipaddress) VALUES (:username, :email1, :bcrypt, now(), :ipaddress)");
        $stmt2->bindParam(':username', $username, PDO::PARAM_STR);
        $stmt2->bindParam(':email1', $email1, PDO::PARAM_STR);
        $stmt2->bindParam(':bcrypt',$bcrypt, PDO::PARAM_STR);
        $stmt->bindParam(':ipaddress', $ipaddress, PDO::PARAM_INT);
        $stmt->execute();
        //get the last id inserted to the db which is now this users id for activation and member folder creation///
        $lastId = $db->lastInsertId();
        $stmt3 = $db->prepare("INSERT INTO activate (user, token) VALUES (:lastId , :token)");
        $stmt3->bindValue(':lastId', $lastId, PDO::PARAM_STR);
        $stmt3->bindValue(':token', $token, PDO::PARAM_STR);
        $stmt3->execute();
        //send email activation to new user///
        $from = "From: Auto Responder @ geekifyme <admin@geekifyme.org>";
        $subject = "IMPORTANT: Activate your geekifyme account";
        $link = "http://www.geekifyme.org/scripts/activate.php?user='.$lastId.'$token='.$token.";
        //strt email body////
        $message = "
        Thanks for registering an account at GeekifyMe!  There is just one last step in setting up your account.  Please click the link below to confirm your identity and get started.  If the link below is not active please copy and paste it into your browser bar.

        $link
        ";
        //set headers////
        $headers = 'MIME-Version: 1.0' . "rn";
        $headers .= "Content_type: textrn";
        $headers .=  "From: $fromrn";
        //send the email now/////
        mail($email1, $subject, $message, $headers);
        $db->commit();
        echo 'Thanks for joining! Check your email in a few moments to activate your account so that you may log in.';
        $db = null;
        exit();
    }
    catch(PDOException $e){
        $db->rollBack();
        echo $e->getMessage();;
        $db = null;
        exit();
    }

是什么原因造成的？

SQLSTATE [HY093]：无效的参数编号：绑定变量的数量与令牌的数量不匹配

我看不到任何基本的遗忘“：”或任何其他真正基本的烂摊子。 你看到什么了吗

Answer 1

    $stmt2 = $db->prepare("INSERT INTO members (username, email, password, signup_date, ipaddress) VALUES (:username, :email1, :bcrypt, now(), :ipaddress)");
         ^---- note the 2
    $stmt->bindParam(':ipaddress', $ipaddress, PDO::PARAM_INT);
         ^--- note the LACK of a 2
    $stmt->execute();
         ^--- ditto

您将ipaddress参数绑定到一个完全不同的语句。 然后，您尝试执行该完全不同的语句。

Answer 2

您正在创建一个语句对象stmt2

接下来的三行将对此进行引用。

但是紧随其后的下两行引用了stmt ，而不是stmt2 。

在您的代码示例中，我们看不到SQL文本或stmt的准备，也没有看到stmt2的执行。

Answer 3

在第一个插入查询中，您传递5个参数并仅绑定4个参数。检查此参数。我认为可能是错误的。

    $stmt2 = $db->prepare("INSERT INTO members (username, email, password, signup_date, ipaddress) VALUES (:username, :email1, :bcrypt, now(), :ipaddress)");
    $stmt2->bindParam(':username', $username, PDO::PARAM_STR);
    $stmt2->bindParam(':email1', $email1, PDO::PARAM_STR);
    $stmt2->bindParam(':bcrypt',$bcrypt, PDO::PARAM_STR);
    $stmt2->bindParam(':ipaddress', $ipaddress, PDO::PARAM_INT);
    $stmt2->execute();

将此行替换为您的代码并进行检查。