[英]How to get browser name,version?
我已经编写了用于检测bworser名称的脚本,以下是OS和broser vesion的代码。
function getBrowser()
{
$u_agent = $_SERVER['HTTP_USER_AGENT'];
$bname = 'Unknown';
$platform = 'Unknown';
$version= "";
$ub = "";
//First get the platform?
if (preg_match('/linux/i', $u_agent)) {
$platform = 'linux';
}
elseif (preg_match('/macintosh|mac os x/i', $u_agent)) {
$platform = 'mac';
}
elseif (preg_match('/windows|win32/i', $u_agent)) {
$platform = 'windows';
}
// Next get the name of the useragent yes seperately and for good reason
if(preg_match('/MSIE/i',$u_agent) && !preg_match('/Opera/i',$u_agent))
{
$bname = 'Internet Explorer';
$ub = "MSIE";
}
elseif(preg_match('/Firefox/i',$u_agent))
{
$bname = 'Mozilla Firefox';
$ub = "Firefox";
}
elseif(preg_match('/Chrome/i',$u_agent))
{
$bname = 'Google Chrome';
$ub = "Chrome";
}
elseif(preg_match('/Safari/i',$u_agent))
{
$bname = 'Apple Safari';
$ub = "Safari";
}
elseif(preg_match('/Opera/i',$u_agent))
{
$bname = 'Opera';
$ub = "Opera";
}
elseif(preg_match('/Netscape/i',$u_agent))
{
$bname = 'Netscape';
$ub = "Netscape";
}
// finally get the correct version number
$known = array('Version', $ub, 'other');
$pattern = "#(?<browser>" . join("|", $known) .")[/]+(?<version>[0-9.|a-zA-Z.]*)#";
if (!preg_match_all($pattern, $u_agent, $matches)) {
// we have no matching number just continue
}
// see how many we have
$i = count($matches['browser']);
if ($i != 1) {
//we will have two since we are not using 'other' argument yet
//see if version is before or after the name
if (strripos($u_agent,"Version") < strripos($u_agent,$ub)){
$version= $matches['version'][0];
}
else {
$version= $matches['version'][1];
}
}
else {
$version= $matches['version'][0];
}
// check if we have a number
if ($version==null || $version=="") {$version="?";}
return array(
'userAgent' => $u_agent,
'name' => $bname,
'version' => $version,
'platform' => $platform,
'pattern' => $pattern
);
}
此脚本仅返回broser名称,平台(操作系统名称),而不返回brwoser的版本。 我不知道是什么问题。
上面的脚本给了我Windows服务器上浏览器名称和版本的输出,但没有连接到亚马逊服务器上。
如果还有其他获取浏览器名称的方法,请提出建议。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.