[英]MySQL join / sum value from one table colum with a count values from another
表1-“新闻”
--------------------------------------
|news_id|news_title|fb_comments_count|
--------------------------------------
| 1| XYZ| 0|
| 2| ABC| 32|
| 3| DEF| 5|
--------------------------------------
表2-“ news_comments”
------------------------------
|com_id| news_id| comment|
------------------------------
| 1| 1| blablabla|
| 2| 2| test |
| 3| 1| comment |
| 4| 1| asdf |
------------------------------
我需要获得每个新闻的总评论总数,其中,Facebook评论从第一张表开始计数,而每个特定新闻在另一张表中的评论总数都被计算在内。
这样-“总评论”:
-----------------------------------
| id | news_id | total comments (fb_comments + count of comments from comments table)
-----------------------------------
| 1| 2 | 33|
| 2| 3 | 5|
| 3| 1 | 3|
-----------------------------------
提前致谢! :)
一个简单的联接和group by可以使用COUNT()来计算您的所有评论。 然后只需将其添加到fb_comment_count。 我们使用LEFT JOIN
来确保它还包含news_comments中未出现的news_id,并将COUNT()仅应用于c.com_id,以确保在没有news_comments的news_comments的情况下,该值将为0。
SELECT n.news_id, COUNT(c.com_id) + n.fb_comments_count AS total_comments
FROM news n
LEFT OUTER JOIN news_comments c ON c.news_id = n.news_id
GROUP BY n.news_id, n.fb_comments_count
SET @rank=0;
SELECT @rank:=@rank+1 AS id,t.*
FROM(
SELECT n.news_id,
(COALESCE(nc.totalComments,0) + n.fb_comments_count) AS total_comments
FROM news n
LEFT JOIN
(
SELECT news_id,COUNT(*) as totalComments
FROM news_comments
GROUP BY news_id
)nc
ON n.news_id = nc.news_id
ORDER BY total_comments desc
) t
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