在新查询中使用从SCOPE_IDENTITY返回的ID

Question

现在，这就是我所拥有的：

$query = "INSERT INTO COMMENTS VALUES ('$user', '$comment', '$star')"; 
mssql_query($query, $connection);
$commentIDQuery = "SELECT SCOPE_IDENTITY() AS ins_id";
$CI = mssql_query ($commentIDQuery, $connection);
$commentID = mssql_fetch_row($CI);
$idQuery = "SELECT recipeid FROM t_recipe WHERE recipename = '$recipeName'";
$RID = mssql_query($idQuery, $connection);
$recipeID = mssql_fetch_row($RID);  
$rcQuery = "INSERT INTO COMMENT_RECIPE VALUES ('$commentID[0]', '$recipeID[0]')";
    mssql_query($rcQuery, $connection);

那么我将如何获得该ins_id？

它将其添加到第一个表，即注释，而不是关系表。

使用SQL Server 2008

Answer 1

那这个呢......

$query = "DECLARE @NewID INT
          INSERT INTO COMMENTS VALUES ('$user', '$comment', '$star');
          SELECT @NewID  = SCOPE_IDENTITY();
          INSERT INTO COMMENTS_RECIPE VALUES (@NewID, '$recipeid')";

$stmt = sqlsrv_query($conn,$query);