[英]PHP. Unable to consume remote web service using WAMP server
我正在使用 WAMP 服务器并尝试读取远程 Web 服务。 我收到以下错误 -
警告:simplexml_load_file( http://example.com/search-api/search/devapi/coupons?format=xml&key=xxxxxxxx&searchloc=30043 ): 无法打开流:HTTP 请求失败! HTTP/1.1 400 Bad Request in C:\\wamp\\www\\php\\ws.php 第 7 行
下面是我的代码。
if( ! $xml = simplexml_load_file('http://example.com/search-api/search/devapi/coupons?format=xml&key=xxxxxxxx&searchloc=30043') )
{
echo 'unable to load XML file';
}
else
{
echo 'xml loaded successfully';
}
解决方案1
您可以使用file_get_contents
尝试这个 -
print_r( simplexml_load_string( file_get_contents("http://pubapi.atti.com/search-api/search/devapi/search?searchloc=78597&term=pizza&format=xml&sort=distance&radius=5&listingcount=10&key=gmj3x7mhsh%22") ) );
解决方案2
function get_data($url){
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.0.3705; .NET CLR 1.1.4322; Media Center PC 4.0)');
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$url = 'http://pubapi.atti.com/search-api/search/devapi/search?searchloc=78597&term=pizza&format=xml&sort=distance&radius=5&listingcount=10&key=gmj3x7mhsh%22';
$result = get_data($url);
print_r(simplexml_load_string($result));
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