Linq查询如何选择所有列

Question

我有一个linq查询，它给了我想要的输出：

 var data = (from c in dtskip.AsEnumerable()
                        select new[]  { 
                         c.Field<string>("Suburb"), c.Field<string>("Postcode"), c.Field<string>("State"),c.Field<string>("ID"), c.Field<string>("SEARCHKEY"), c.Field<string>("RATING"), c.Field<string>("DELIVERY")
                       });

如何选择所有列而不是像c.field<string>("postcode")那样给出名称。我的输出是仅来自数据表dtskip的数据：

输出：

["DARWIN","0800","NT","2","DARWINNT","A","Delivery Area"]
,["ALAWA","0810","NT","5","ALAWANT","A","Delivery Area"],
["BRINKIN","0810","NT","6","BRINKINNT","A","Delivery Area"],

有没有其他方法我可以使用linq查询从数据表中获取输出。

Answer 1

你有没有尝试过

var data = (From c in dtskip
            select c).AsEnumerable(); //Not sure about the AsEnumerable :s

Answer 2

DataRow包含一个ItemArray成员，该成员将该行中的所有数据作为数组返回，缺点是它们都作为object返回，但如果所有列都是相同类型，则可以将ItemArray转换为所需类型（在此案例string ）

dtskip.Rows.Cast<DataRow>().Select(r => r.ItemArray.Cast<string>());

这将为您提供一个IEnumerable<IEnumerable<string>> 。

Answer 3

你在找这样的东西吗？

var data = dtskip.AsEnumerable().
            Select(x => new 
                   { 
                              Suburb = x.Field<string>("Suburb"),
                              Postcode= x.Field<string>("Postcode"),
                              State= x.Field<string>("State"),
                              Id= x.Field<string>("ID"),
                              Searchkey = x.Field<string>("SEARCHKEY"),
                              Rating = x.Field<string>("RATING"),
                              Delivery = x.Field<string>("DELIVERY")
                   });