[英]Aggregate sum of a field when another row with the same ID is selected in SQL
我有两张桌子
CREATE TABLE users
(
id int
);
CREATE TABLE attributes
(
user_id int,
k char(100),
v char(100)
);
insert into users values (1);
insert into users values (2);
insert into users values (3);
insert into attributes values (1, 'k1', 'v1');
insert into attributes values (1, 'k2', 2);
insert into attributes values (2, 'k1', 'v1');
insert into attributes values (2, 'k2', 7);
insert into attributes values (3, 'k1', 'v2');
insert into attributes values (3, 'k2', 11);
我想要的是
v1
,将同一user_id
下另一行的值求和,并得出k=k2
所以我想要像
v1 9
v2 11
当前的SQL:
SELECT v, '?' as total
FROM users
JOIN attributes ON users.id = attributes.user_id
WHERE k = 'k1'
GROUP BY v
这正是您所需要的。 不过,我完全同意aardvarkk的观点,最终明智的选择可能只是简化您的架构。 无论如何..
SELECT a1.v, SUM(a2.v) FROM users u
INNER JOIN attributes a1 ON a1.user_id = u.id
INNER JOIN attributes a2 ON a2.user_id = a1.user_id AND a2.k = 'k2'
WHERE a1.k = 'k1'
GROUP BY a1.v
create table sumv
(
vnmbr nchar(2),
v int
)
declare @nmbr nvarchar
set @nmbr = 1
while @nmbr < 3
begin
insert into sumv (vnmbr,v)
select 'v'+@nmbr,v from attributes where [user_id] in (select [user_id] from attributes
where v = 'v'+@nmbr) and v not like 'v%'
set @nmbr = @nmbr + 1
end
select vnmbr,sum(v) as [sumv] from sumv group by vnmbr
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