[英]Aggregating a column by multiple date ranges in a single query
我有一个包含5列的MySQL表:
Device | Name | Date | Source | Income
设备 , 名称和来源都不是唯一的。
我正在尝试编写SQL以获取以下内容:
Device | Name | Source | Income (for last 3 days) | Income (for last 9 days) | Income (for last 12 days)
做这个的最好方式是什么?
您可以通过CASE
语句获取条件SUM()
:
SELECT Device
,Name
,Source
,SUM(CASE WHEN date BETWEEN UNIX_TIMESTAMP(NOW() - INTERVAL 3 day) AND UNIX_TIMESTAMP(NOW()) THEN Income END) AS Last_3_Days
,SUM(CASE WHEN date BETWEEN UNIX_TIMESTAMP(NOW() - INTERVAL 9 day) AND UNIX_TIMESTAMP(NOW()) THEN Income END) AS Last_9_Days
FROM YourTable
GROUP BY Device
,Name
,Source
SELECT COUNT(*) as total_l3d FROM table WHERE DATEDIFF(Date, NOW()) <= 3
UNION
SELECT COUNT(*) as total_l9d FROM table WHERE DATEDIFF(Date, NOW()) <= 9
UNION
SELECT COUNT(*) as total_l12d FROM table WHERE DATEDIFF(Date, NOW()) <= 12
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.