如何选择不同的记录

Question

我想从我的数据中选择不同的记录，因为它会显示重复的记录。 这是我的查询的样子：

SELECT DISTINCT ID,
  FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee 

我加入了不同的词，但仍然得到重复的结果

Answer 1

DISTINCT关键字与该列一起使用，您想获得不同的值，ID始终是不同的。 由于DISTINCT FirstName比名字将不同。

Answer 2

您正在寻找：

SELECT FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee 

要么

SELECT ID,
  FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY ID, 
FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee 

Answer 3

您可以使用row_number（）和by（）分区来获得所需的结果

尝试这样：

select * from
(
select *,rn=row_number()over(partition by Totalawards,totalrespect order by Firstname)
from table
)x
where x.rn=1