[英]Looking for a REGEXP for a number upto two decimal places
我正在尝试这个
/-?(?:\d+|\d{1,3}(?:,\d{3})+)?(?:\.\d+)?$/
但这要超过两个小数位,并且它接受值“ .00”
它应该接受以下值
100.00
00.00
0
100
10000000000.00
98173827827.82
它应该拒绝以下值.00
10.098
87.89381938193819
9183983109.9283912
10.aa
adjbdjbdj
我是新来的正则表达式
PS:-我正在尝试以下代码进行JavaScript处理。 因此,请将表达式限制为仅javascript。
提前致谢
这个应该做的:
/^\d+(\.\d{1,2})?$/
我会做类似的事情:
/-?(?:\d{1,3}(?:,?\d{3})+)?(?:\.\d{1,2})?$/
尝试这个:
if (/^\d+([,.]\d{1,2})?$/im.test(value)) {
alert("ACCEPTED\n" + value);
} else {
alert("REJECTED\n" + value);
}
}
正则表达式说明
^\d+([,.]\d{1,2})?$
Assert position at the beginning of a line (at beginning of the string or after a line break character) (line feed, line feed, line separator, paragraph separator) «^»
Match a single character that is a “digit” (ASCII 0–9 only) «\d+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regex below and capture its match into backreference number 1 «([,.]\d{1,2})?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single character from the list “,.” «[,.]»
Match a single character that is a “digit” (ASCII 0–9 only) «\d{1,2}»
Between one and 2 times, as many times as possible, giving back as needed (greedy) «{1,2}»
Assert position at the end of a line (at the end of the string or before a line break character) (line feed, line feed, line separator, paragraph separator) «$»
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