从Ajax jQuery File接收Php中的数据
[英]Receive data in Php from Ajax jQuery File
问题描述
我知道php一些基本知识。 但是我从来没有使用过ajax 。 现在，我得到了一个联系人文件，他们在其中使用ajax将数据传递到php文件。 我真的不知道该怎么做。
请帮助我。
contact.js：
$.ajax({
type: "POST",
url : "send.php",
data: "name=" + name + "&email=" + email + "&subject=" + "You Got Email" + "&message=" + message,
success: function(data){
if(data == 'success'){
$("#btnsubmit").remove();
$("#mail_success").fadeIn(500);
}else{
$("#mail_failed").html(data).fadeIn(500);
$("#send").removeAttr("disabled").attr("value", "send");
}
}
});
我不知道这是否正确，但是我知道很多，所以我自己创建了send.php文件。 检查一下。
send.php：
<?php
$name = $_POST["name"];
$email = $_POST["email"];
$subject = $_POST["subject"];
$message = $_POST["message"];
$mail_sub= $subject;
$mail_from = "$email"; // applicant email id. it must be dynamic.
$mail_body = "<html> <body>";
$mail_body .= '<table style="" cellpadding="3">';
$mail_body .= "
<tr>
<td width='120'> <strong> Name </strong> </td>
<td width='8'> : </td>
<td width='300'> $name </td>
</tr>
<tr>
<td> <strong> Email </strong> </td>
<td> : </td>
<td> $email </td>
</tr>
<tr>
<td> <strong> Message </strong> </td>
<td> : </td>
<td> $message </td>
</tr>
</table>
</body> </html>";
$header = "From: $name<$email>\r\n";
$header .= "MIME-Version: 1.0\n";
$header .= "Content-Type: text/html; charset=\"iso-8859-1\"\n";
$header .= "X-Priority: 1\n";
$header .= "X-MSMail-Priority: High\n";
$header .= "X-Mailer: PHP / ".phpversion()."\r\n";
$header .= "Importance: High\n";
$mail_to= 'in@example.com'; // receiver email address.
?>
如何实现呢？ 我想按照js文件发送电子邮件并返回消息。
1 个解决方案
解决方案1
0 2014-05-15 11:28:32
phppart
<?php
$name = $_POST["name"];
$email = $_POST["email"];
$subject = $_POST["subject"];
$message = $_POST["message"];
$mail_sub= $subject;
$mail_from = "$email"; // applicant email id. it must be dynamic.
$mail_body = "<html> <body>";
$mail_body .= '<table style="" cellpadding="3">';
$mail_body .= "
<tr>
<td width='120'> <strong> Name </strong> </td>
<td width='8'> : </td>
<td width='300'> $name </td>
</tr>
<tr>
<td> <strong> Email </strong> </td>
<td> : </td>
<td> $email </td>
</tr>
<tr>
<td> <strong> Message </strong> </td>
<td> : </td>
<td> $message </td>
</tr>
</table>
</body> </html>";
$header = "From: $name<$email>\r\n";
$header .= "MIME-Version: 1.0\n";
$header .= "Content-Type: text/html; charset=\"iso-8859-1\"\n";
$header .= "X-Priority: 1\n";
$header .= "X-MSMail-Priority: High\n";
$header .= "X-Mailer: PHP / ".phpversion()."\r\n";
$header .= "Importance: High\n";
$mail_to= 'in@example.com'; // receiver email address.
$isvalid = false;
if(mail($mail_to, $mailsub, $mail_body, $header)){
$isvalid = true;
}
echo json_encode($isvalid);
jQuery部分
$.ajax({
type: "POST",
url : "send.php",
data: "name=" + name + "&email=" + email + "&subject=" + "You Got Email" + "&message=" + message,
success: function(data){
var response = jQuery.parseJSON(data);
if(response.isvalid == true){
$("#btnsubmit").remove();
$("#mail_success").fadeIn(500);
}else{
$("#mail_failed").html(data).fadeIn(500);
$("#send").removeAttr("disabled").attr("value", "send");
}
}
});
Andd umm应该这样做！
无法从ajax接收数据到php变量
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.