MDX交叉联接仅在成员相等的情况下

Question

是否可以交叉加入并仅在两个成员相等的情况下返回？ 例如，针对SSAS 2012中的Adventure Works的以下查询

select [Measures].[Reseller Sales Amount] on 0
,topcount(([Ship Date].[Date].Children,[Delivery Date].[Date].Children),5) on 1
from [Adventure Works]

将返回以下值

                     Reseller Sales Amount
January 1, 2005 January 1, 2005 (null)
January 1, 2005 January 2, 2005 (null)
January 1, 2005 January 3, 2005 (null)
January 1, 2005 January 4, 2005 (null)
January 1, 2005 January 5, 2005 (null)

我想要的结果如下

                     Reseller Sales Amount
January 1, 2005 January 1, 2005 (null)
January 2, 2005 January 2, 2005 (null)
January 3, 2005 January 3, 2005 (null)
January 4, 2005 January 4, 2005 (null)
January 5, 2005 January 5, 2005 (null)

是否可以通过使用MDX查询（不使用交叉联接）来获得如下所示的结果？

Answer 1

这应该为您工作。 基本上，我创建一个布尔样式的计算成员，然后将该成员包括在TOPCOUNT函数中。

希望对您有所帮助。

灰

WITH MEMBER [Measures].[MatchingDates] AS
IIF([Ship Date].[Date].MEMBERVALUE = [Delivery Date].[Date].MEMBERVALUE,1,0)
SELECT
[Measures].[Reseller Sales Amount] ON 0
,   TOPCOUNT({[Ship Date].[Date].[Date].MEMBERS * [Delivery Date].[Date].[Date].MEMBERS},5,[Measures].[MatchingDates]) ON 1
FROM
[Adventure Works]