如何使用查询结果选择Sql Server中的另一个表

Question

嗨，我是新来的。 我在选择查询结果到另一个数据库时遇到问题。

<?php
include_once("config.php");
$connectionInfo = array( "Database"=>"rohanstat", "UID"=>$UID, "PWD"=>$PASS);
$conn = sqlsrv_connect( $serverName, $connectionInfo);
$conn = sqlsrv_connect( $serverName, $connectionInfo);
$sql2 = "SET ROWCOUNT 15 SELECT   attacker, COUNT(attacker) AS dupe_cnt FROM [rohanstat].[dbo].[TPKill]
GROUP BY attacker
HAVING   COUNT(attacker) > 0
ORDER BY COUNT(attacker) DESC";
$stmt2 = sqlsrv_query( $conn, $sql2);
while($rows = sqlsrv_fetch_array($stmt2))
echo $rows ['attacker']."<br>";
?>

我只想使用$rows['attacker']选择另一个数据库。 这意味着我想这样使用它。

sql = "select * from [RohanGame].[dbo].[TCharacter] where name = $rows ['attacker'];

提前致谢。

Answer 1

您可以简单地使用IN ：

SELECT  *
FROM    [RohanGame].[dbo].[TCharacter] 
WHERE   name IN 
        (   SELECT   TOP 15 attacker
            FROM [rohanstat].[dbo].[TPKill]
            GROUP BY attacker
            HAVING   COUNT(attacker) > 0
            ORDER BY COUNT(attacker) DESC
        );

或者，如果您需要COUNT，则可以将结果结合在一起：

SELECT  tc.*, a.Dupe_cnt
FROM    [RohanGame].[dbo].[TCharacter]  tc
        INNER JOIN
        (   SELECT   TOP 15 attacker, COUNT(attacker) AS dupe_cnt 
            FROM [rohanstat].[dbo].[TPKill]
            GROUP BY attacker
            HAVING   COUNT(attacker) > 0
            ORDER BY COUNT(attacker) DESC
        ) a
            ON a.Attacker = tc.name;

我认为这不会有太大变化，但是您可以换掉：

HAVING   COUNT(attacker) > 0

与

WHERE   attacker IS NOT NULL

由于您已经按攻击者分组，因此COUNT(attacker)不为空的唯一组就是COUNT(attacker)为空的组：

SELECT  tc.*, a.Dupe_cnt
FROM    [RohanGame].[dbo].[TCharacter]  tc
        INNER JOIN
        (   SELECT   TOP 15 attacker, COUNT(*) AS dupe_cnt 
            FROM [rohanstat].[dbo].[TPKill]
            WHERE attacker IS NOT NULL
            GROUP BY attacker
            ORDER BY COUNT(*) DESC
        ) a
            ON a.Attacker = tc.name;

Answer 2

您对该问题的标记是SQL； SQL服务器

但对于mySQL Oracle和其他数据库是相同的

在这里我回答T-SQL中的其他问题

您可以通过两种方式在PHP中从DB1读取内存，然后打开连接并向DB2做逻辑

或在T-SQL中可以在一个查询中完成

从表1复制到表2，并将日期插入7天还是14天？

Answer 3

如果您还想要使用PHP的解决方案，即已声明的$rows变量，则可以执行以下操作：

$attackers = "";
foreach($rows as $row) {
  $attackers .= "$row,";
}
//Get rid of the last comma
$attackers = rtrim($attackers, ',');
$sql = sprintf("select * from [RohanGame].[dbo].[TCharacter] where name IN (%s)", $attackers);