从VB转换为C＃：bitmap.save（）参数错误

Question

我正在将一段代码转换为c＃，由于参数无效，在bitmap.save（）处出现错误。 转换后的代码为：

System.Drawing.Bitmap picture = (System.Drawing.Bitmap)System.Drawing.Bitmap.FromFile(FilePath);
System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap(w1, h1);
System.Drawing.Graphics gr_dest = System.Drawing.Graphics.FromImage(bitmap);
gr_dest.InterpolationMode = System.Drawing.Drawing2D.InterpolationMode.HighQualityBicubic;

gr_dest.DrawImage(picture, -x1, -y1, effective_width, effective_height);

System.IO.Stream output = new System.IO.MemoryStream();
System.Drawing.Imaging.EncoderParameters encoderParams = new System.Drawing.Imaging.EncoderParameters(1);
System.Drawing.Imaging.EncoderParameter encoderParam = new System.Drawing.Imaging.EncoderParameter(System.Drawing.Imaging.Encoder.Quality, 96);
encoderParams.Param[0] = encoderParam;
System.Drawing.Imaging.ImageCodecInfo ici = GetEncoderInfo("image/jpeg");
bitmap.Save(output, ici, encoderParams);

关于为什么这种方法失败的任何想法？

Answer 1

质量必须是长期价值，因此请更改：

(System.Drawing.Imaging.Encoder.Quality, 96)

至：

(System.Drawing.Imaging.Encoder.Quality, 96L)