[英]How do I modify this MySQL INSERT Query for multiple rows?
我正在尝试插入艺术家,歌曲和唱片标签的记录,同时检查数据库中是否不存在该数据。
以下代码来自Mike Fenwick 。
<?php
$query = "SELECT id FROM table WHERE unique1=value1 AND unique2=value2…";
$select_result = mysql_query($query);
if (!mysql_num_rows($select_result)) {
$query = "INSERT INTO table SET unique1=value1 AND unique2=value2…";
$insert_result = mysql_query($query);
$id = mysql_insert_id();
}
else {
$row = mysql_fetch_assoc($select_result);
$id = $row['id'];
}
return $id;
?>
我需要修改它以检查是否已经存在三个唯一值(来自3个单独的表),如果不存在,请插入它们。 这是我的尝试:
<?php
$query = "SELECT id FROM artistsTable WHERE artistName='Beyonce'";
$select_result = mysql_query($query);
if (!mysql_num_rows($select_result)) {
$query = "INSERT INTO table SET artistName='Beyonce' AND artistImage='beyonce.jpg'";
$insert_result = mysql_query($query);
$artistID = mysql_insert_id();
}
else {
$row = mysql_fetch_assoc($select_result);
$artistID = $row['artistID'];
}
return $artistID;
$query = "SELECT id FROM recordLabelTable WHERE labelName='Columbia Records'";
$select_result = mysql_query($query);
if (!mysql_num_rows($select_result)) {
$query = "INSERT INTO table SET labelName='Columbia Records'";
$insert_result = mysql_query($query);
$labelID = mysql_insert_id();
}
else {
$row = mysql_fetch_assoc($select_result);
$labelID = $row['labelID'];
}
return $labelID;
$query = "SELECT id FROM songTable WHERE trackTitle='Crazy in Love' AND artistID=".$artistID." AND labelID=".$labelID."";
$select_result = mysql_query($query);
if (!mysql_num_rows($select_result)) {
$query = "INSERT INTO songTable SET trackTitle='Crazy in Love' AND artistID=".$artistID." AND labelID=".$labelID."";
$insert_result = mysql_query($query);
$songID = mysql_insert_id();
}
else {
$row = mysql_fetch_assoc($select_result);
$songID = $row['songID'];
}
return $songID;
?>
我假设必须有一种更有效的方法来执行此操作。 任何想法将不胜感激。
使用基本的插入/忽略语法,您可以执行以下操作。
插入几个插入艺术家的详细信息和标签的详细信息,然后基于SELECT插入:
<?php
$query = "INSERT IGNORE INTO artistTable (artistName, artistImag) VALUES('Beyonce', 'beyonce.jpg')";
$insert_result = mysql_query($query);
$query = "INSERT IGNORE INTO labelTable (labelName) VALUES('Columbia Records')";
$insert_result = mysql_query($query);
$query = "INSERT IGNORE INTO songTable (trackTitle, artistID, labelID)
SELECT 'Crazy in Love', a.artistID, b.labelID
FROM artistTable a
INNER JOIN labelTable b
ON a.artistName = 'Beyonce'
AND a.artistImag = 'beyonce.jpg'
AND b.labelName = 'Columbia Records'";
$insert_result = mysql_query($query);
$songID = mysql_insert_id();
return $songID;
?>
正如@LoganWayne所说,您可能应该使用MySQLi。
<?php
/* ESTABLISH CONNECTION */
$con=mysqli_connect("Host","Username","Password","Database"); /* REPLACE NECESSARY DATA */
if(mysqli_connect_errno()){
echo "Error".mysqli_connect_error();
}
/* FOR artistsTable TABLE */
$query = "SELECT id FROM artistsTable WHERE artistName='Beyonce'";
$select_result = mysqli_query($con,$query); /* EXECUTE QUERY */
if (mysqli_num_rows($select_result)==0) { /* IF QUERY'S RESULT IS 0 */
$query = "INSERT INTO table SET artistName='Beyonce' AND artistImage='beyonce.jpg'";
$insert_result = mysqli_query($con,$query); /* EXECUTE INSERT QUERY */
} /* END OF IF */
else {
while($row = mysqli_fetch_array($select_result)){
$artistID = mysqli_real_escape_string($con,$row['artistID']); /* ESCAPE STRING */
} /* END OF WHILE LOOP */
} /* END OF ELSE */
/* FOR recordLabelTable TABLE */
$query = "SELECT id FROM recordLabelTable WHERE labelName='Columbia Records'";
$select_result = mysqli_query($con,$query); /* EXECUTE SELECT QUERY */
if (mysqli_num_rows($select_result)==0) { /* IF QUERY'S RESULT IS 0 */
$query = "INSERT INTO table SET labelName='Columbia Records'";
$insert_result = mysqli_query($con,$query); /* EXECUTE INSERT QUERY */
}
else {
while($row = mysqli_fetch_array($select_result)){
$labelID = mysqli_real_escape_string($con,$row['labelID']); /* ESCAPE STRING */
}
}
/* FOR songtable TABLE */
$query = "SELECT id FROM songTable WHERE trackTitle='Crazy in Love' AND artistID='$artistID' AND labelID='$labelID'";
$select_result = mysqli_query($con,$query); /* EXECUTE SELECT QUERY */
if (mysqli_num_rows($select_result)==0) {
$query = "INSERT INTO songTable SET trackTitle='Crazy in Love' AND artistID='$artistID' AND labelID='$labelID'";
$insert_result = mysqli_query($con,$query); /* EXECUTE QUERY */
} /* END OF IF */
else {
while($row = mysqli_fetch_array($select_result)){
$songID = mysqli_real_escape_string($con,$row['songID']);
} /* END OF WHILE LOOP */
}
?>
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