[英]SQL Server - Generate a column value which satisfy same condition in a day
[英]Get column names in SQL server that satisfy a where condition on data
我只是在使用SQL服务器时有一个随机的疑问,我认为我可以在这里弄清楚它。 说-我有一个条件,我想找出数据库中满足我的where条件的所有列名称。
示例:-SQL-Server DB中有一些20-30个表。现在,我需要的是查询以查找具有“ Ritesh”作为数据字段的列名称列表。 首先,我不知道这是否真的可能。
我希望我很清楚。 请任何帮助将不胜感激。
谢谢。 里特什
这应该可行,但是请注意,在大型数据库中执行该过程将需要一段时间。 我假设搜索字符串可能只是其中包含的数据的一部分,并且正在使用通配符。 我觉得这纯粹是学术性的,因为我无法想象需要这样做的情况。
--you need to iterate the whole columns of entire table to find the matched record
--another thing is that you need dynamic sql to find the table name
DECLARE @Value varchar(50) --value for that find the column Name
SET @Value = 'Ritesh'
CREATE TABLE #Table
(
TableName Varchar(500),ColumnName Varchar(500),
Id int Identity(1,1) --use for iteration
)
CREATE TABLE #Results
(
TableName varchar(500),
ColumnName varchar(500)
)
INSERT INTO #Table
SELECT
TABLE_SCHEMA + '.' + TABLE_NAME AS TableNam,
Column_name AS ColumnName
FROM INFORMATION_SCHEMA.COLUMNS
WHERE Data_type IN ('char', 'nchar', 'varchar', 'nvarchar')
--change the datatype based on the datatype of sample data you provide
-- also remember to change the wildcard, if the input datatype is not a string
DECLARE @Count Int --total record to iterated
SET @Count = 0;
SELECT
@Count = COUNT(*)
FROM #Table
DECLARE @I int --initial value one to iterate
SET @I = 1;
DECLARE @TableName varchar(500)
SET @TableName = ''
DECLARE @ColumnName varchar(500)
SET @ColumnName = ''
DECLARE @Str nvarchar(1000)
SET @Str = ''
DECLARE @param nvarchar(1000)
SET @param = ''
DECLARE @TableNameFound varchar(max)
SET @TableNameFound = ''
DECLARE @Found bit
SET @Found = 0;
WHILE @I<=@Count
BEGIN
SET @Found = 0;
SELECT
@TableName = TableName,
@ColumnName = ColumnName
FROM #Table
WHERE Id = @I;
SET @param = '@TableName varchar(500),@ColumnName varchar(500),@Value varchar(50),@TableNameFound varchar(max),@Found bit output'
SET @str = 'Select @Found=1 From ' + @TableName + ' where ' + @ColumnName + ' Like ' + '''' + '%' + @Value + '%' + ''''
-- here we are using tablename and actual value to find in table
EXEC sp_executesql @str,
@param,
@TableName,
@ColumnName,
@Value,
@TableNameFound,
@Found OUTPUT
IF @Found=1
BEGIN
INSERT INTO #Results (TableName, ColumnName)
SELECT
@TableName,
@ColumnName
END
--increment value of @I
SET @I = @I + 1;
END
--Display Results
SELECT * FROM #Results
--Clean Up
DROP TABLE #Table
DROP TABLE #Results
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