[英]sql-server: Combing these 2 queries results into 1
我有这两个创建排名列表的查询,然后从结果中选择特定的行,因此两个查询均返回1值。 如何合并结果,以便将它们一起返回。 符合逻辑的东西:
SELECT x.a, y.b FROM (SELECT * from a) as x, (SELECT * FROM b) as y
查询1
declare @MainHospital varchar(50)='Hospital1';
WITH cte AS (
SELECT 4 score, growth1 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 3 score, growth2 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 2 score, growth3 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 1 score, growth4 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 0 score, growth5 area FROM Survey
WHERE MainHospital = @MainHospital
),
cte2 AS (
SELECT area, SUM(score) score FROM cte
GROUP BY area
HAVING area IS NOT NULL
),
cte3 AS (
SELECT area, score,
Row_Number() OVER (ORDER BY score DESC) row,
RANK() OVER (ORDER BY score DESC) rank
FROM cte2
)
SELECT top 1 area AS Growth
FROM cte3
WHERE row = 1
query2
WITH Ecte AS (
SELECT 4 score, Efficiency1 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 3 score, Efficiency2 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 2 score, Efficiency3 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 1 score, Efficiency4 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 0 score, Efficiency5 area FROM Survey
WHERE MainHospital = @MainHospital
), Ecte2 AS (
SELECT area, SUM(score) score FROM Ecte
GROUP BY area
HAVING area IS NOT NULL
), Ecte3 AS (
SELECT area, score,
Row_Number() OVER (ORDER BY score DESC) row,
RANK() OVER (ORDER BY score DESC) rank
FROM Ecte2
)
SELECT TOP 1 area as Efficiency
FROM Ecte3
WHERE row = 1
您是否看过UNION
/ UNION ALL
? 您必须在每个返回中具有相同的列数,此功能才能起作用。
例如:
SELECT COL1, COL2, COL3 FROM TABLE1
UNION ALL
SELECT COL1, COL2, COL3 FROM TABLE2
对于CTE,请执行以下操作:
;WITH CTE1 (col1, col2)
AS
(
SELECT col1, col2
FROM ...
)
, CTE2 (col1, col2)
AS
(
SELECT col1, col2
FROM ....
)
SELECT col1, col2
FROM CTE1
WHERE something = true
UNION ALL
SELECT col1, col2
FROM CTE2
WHERE something = true
注意: UNION ALL
将返回重复的行, UNION
将消除相同的行,就好像所选的每一列上的GROUP BY
。
您的代码将更改如下:
declare @MainHospital varchar(50)='Hospital1';
WITH cte AS (
SELECT 4 score, growth1 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 3 score, growth2 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 2 score, growth3 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 1 score, growth4 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 0 score, growth5 area FROM Survey
WHERE MainHospital = @MainHospital
),
cte2 AS (
SELECT area, SUM(score) score FROM cte
GROUP BY area
HAVING area IS NOT NULL
),
cte3 AS (
SELECT area, score,
Row_Number() OVER (ORDER BY score DESC) row,
RANK() OVER (ORDER BY score DESC) rank
FROM cte2
),
Ecte AS (
SELECT 4 score, Efficiency1 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 3 score, Efficiency2 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 2 score, Efficiency3 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 1 score, Efficiency4 area FROM Survey
WHERE MainHospital = @MainHospital
UNION ALL
SELECT 0 score, Efficiency5 area FROM Survey
WHERE MainHospital = @MainHospital
), Ecte2 AS (
SELECT area, SUM(score) score FROM Ecte
GROUP BY area
HAVING area IS NOT NULL
), Ecte3 AS (
SELECT area, score,
Row_Number() OVER (ORDER BY score DESC) row,
RANK() OVER (ORDER BY score DESC) rank
FROM Ecte2
)
SELECT TOP 1 area as Efficiency
FROM Ecte3
WHERE row = 1
UNION ALL
SELECT top 1 area AS Growth
FROM cte3
WHERE row = 1
如果要同时使用两个值,请将最终查询更改为此:
SELECT TOP 1 T1.area as Efficiency, T2.area AS Growth
FROM Ecte3 T1, cte3 T2
WHERE T1.row = 1 AND T2.row = 1
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