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MySQL:在单个查询中从数据库和PHP数组中获取值

[英]Mysql: fetch value from database and php array in single query

mixed_menu

mixed_menu

SELECT mixed.unique_id, 
MENU_LABEL 
      case 
          when (--something...)
FROM mixed_menu mixed 
ORDER BY mixed.position ASC

问题:我想编写一个mysql查询,该查询可以在以下情况下检索unique_id,MENU_LABEL。

  • 情况1:

    如果类型=='db_category',则从数据库( 1.db_category )中检索标签 ,其中id = unique_id

  • 情况2:

    如果type =='category',则从php数组( 2.PHP Array )中检索数组值 ,其中array key = unique_id


1. db_category

db_category

2. PHP数组

$category_array = array('car'  => 'All Cars', 
                        'jeep' => 'All Jeeps'
                       );

如果您使用php数组创建了一个新表,则会更容易。

但是使用您当前的结构,您可以创建一个临时/伪表,如下所示

SELECT * FROM (
  SELECT 'car' as `id`, 'All Cars' as `label`
  UNION
  SELECT 'jeep' as `id`, 'All Jeeps' as `label`
) php

因此,您可以使用类似-

SELECT mm.unique_id,

CASE
  WHEN mm.type = 'db_category' THEN dbc.label
  WHEN mm.type = 'category' THEN php.label
END as menu_label

FROM mixed_menu mm

LEFT JOIN db_category dbc ON mm.unique_id = dbc.id

LEFT JOIN (
  /*Create fake table*/
  SELECT 'car' as `id`, 'All Cars' as `label`
  UNION
  SELECT 'jeep' as `id`, 'All Jeeps' as `label`
) php ON mm.unique_id = php.id

ORDER BY mm.position ASC

这里是一个SQLFiddle例子- http://sqlfiddle.com/#!2/5630cc/5

然后,您将需要使用php数组来构建该假表。

编辑

由于您的mixed_menudb_category表是COLLATION latin1_swedish_ci db_category ,并且使用SELECT UNION默认为COLLATION utf8_general_ci您需要在SELECT UNION声明它

SELECT * FROM (
  SELECT 'car' COLLATE latin1_swedish_ci as `id`, 'All Cars' COLLATE latin1_swedish_ci as `label`
  UNION
  SELECT 'jeep' COLLATE latin1_swedish_ci as `id`, 'All Jeeps' COLLATE latin1_swedish_ci as `label`
) php    

所以现在查询将是

SELECT mm.unique_id,

CASE
  WHEN mm.type = 'db_category' THEN dbc.label
  WHEN mm.type = 'category' THEN php.label
END as menu_label

FROM mixed_menu mm

LEFT JOIN db_category dbc ON mm.unique_id = dbc.id

LEFT JOIN (
  /*Create fake table*/
  SELECT 'car' COLLATE latin1_swedish_ci as `id`, 'All Cars' COLLATE latin1_swedish_ci as `label`
  UNION
  SELECT 'jeep' COLLATE latin1_swedish_ci as `id`, 'All Jeeps' COLLATE latin1_swedish_ci as `label`
) php ON mm.unique_id = php.id

ORDER BY mm.position ASC

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