如何在迅捷中比较Enum？

Question

在Objective-C中这很好用

无法在Swift中编译它

要么

IOS SDK中的ALAuthorizationStatus定义

enum ALAuthorizationStatus : Int {
    case NotDetermined // User has not yet made a choice with regards to this application
    case Restricted // This application is not authorized to access photo data.
    // The user cannot change this application’s status, possibly due to active restrictions
    //  such as parental controls being in place.
    case Denied // User has explicitly denied this application access to photos data.
    case Authorized // User has authorized this application to access photos data.
}

Answer 1

比较运算符==返回Bool ，而不是Boolean 。 以下编译：

func isAuthorized() -> Bool {
    let status = ALAssetsLibrary.authorizationStatus()
    return status == ALAuthorizationStatus.Authorized
}

（就个人而言，我发现来自Swift编译器的错误消息有时令人困惑。在这种情况下，问题不是==的参数，而是错误的返回类型。）

---

实际上，由于自动类型推断 ，还应编译以下内容：

func isAuthorized() -> Bool {
    let status = ALAssetsLibrary.authorizationStatus()
    return status == .Authorized
}

但它失败了编译器错误“找不到成员'授权'” ，除非您明确指定status变量的类型：

func isAuthorized() -> Bool {
    let status:ALAuthorizationStatus = ALAssetsLibrary.authorizationStatus()
    return status == .Authorized
}

这可能是当前Swift编译器中的一个错误（使用Xcode 6 beta 1测试）。

更新：第一个版本现在在Xcode 6.1中编译。