[英]SQL average from multiple columns
如何从多个列中获得平均值?
例如:
Columns: ID 125Hz 250Hz 500Hz 750Hz 1000Hz 1500Hz 2000Hz 3000Hz 4000Hz 6000Hz 8000Hz
Values: 1 92 82 63 83 32 43 54 56 54 34 54
我想获取除ID外的所有列的平均值。 我怎么做?
在SQL-SERVER中,您可以使用此
DECLARE @total int
DECLARE @query varchar(550)
DECLARE @ALLColumns VARCHAR(500)
SET @ALLColumns = ''
----Build the string columns
SELECT @ALLColumns = @ALLColumns + '+' + '['+sc.NAME+']'
FROM sys.tables st
INNER JOIN sys.columns sc ON st.object_id = sc.object_id
WHERE st.name LIKE '%YOUR_TABLE_NAME%'
AND sc.NAME LIKE '[0-9]%';--[0-9]% just get the column that start with number
----Get the total number of column,
SELECT @total = count(*) FROM sys.tables st
INNER JOIN sys.columns sc ON st.object_id = sc.object_id
WHERE st.name LIKE '%YOUR_TABLE_NAME%'
AND sc.NAME LIKE '[0-9]%';--[0-9]% just get the column that start with number
SET @query = 'SELECT SUM('+ SUBSTRING(@ALLColumns,2,LEN(@ALLColumns))+')/'
+CAST(@total as varchar(4))+ ' AS [AVG]
FROM [YOUR_TABLE_NAME]
GROUP BY [ID]'
--SELECT @query
EXECUTE(@query)
这将执行如下查询:
SELECT SUM([125Hz]+[250Hz]+[500Hz]+[750Hz]+[1000Hz]+[1500Hz]+[2000Hz]
+[3000Hz]+[4000Hz]+[6000Hz]+[8000Hz])/11 AS [AVG]
FROM [YOUR_TABLE_NAME] GROUP BY [ID]
更新
添加一列存储平均值,我将其命名为[AVG]并修改@query的值以
SET @query = '
CREATE TABLE #Medition (ID int,[AVG] decimal(18,4))
INSERT INTO #Medition (ID,[AVG])
SELECT ID,SUM ('+ SUBSTRING(@ALLColumns,2,LEN(@ALLColumns))+')/'
+CAST(@total as varchar(10))
+ ' AS [AVG] FROM Medition GROUP BY ID
UPDATE YOUR_TABLE_NAME SET YOUR_TABLE_NAME.[AVG] = #Medition.[AVG]
FROM YOUR_TABLE_NAME INNER JOIN #Medition ON YOUR_TABLE_NAME.ID =#Medition.ID
DROP TABLE #Medition
'
注意:构建查询字符串有点丑陋
由于没有可用的内置函数来进行水平聚合,因此您必须手动添加列。
select (125Hz+250Hz+500Hz+750Hz+1000Hz+1500Hz+2000Hz+3000Hz+4000Hz+6000Hz+8000Hz)/11 as aveHz from table_name
SELECT sum(125Hz + 250Hz + 500Hz + 750Hz + 1000Hz + 1500Hz + 2000Hz + 3000Hz +
4000Hz + 6000Hz + 8000Hz)/11 as averageHz from TABLE
这样做的另一种方式,实际上并没有使用魔术数字11
,只是它有些冗长。
WITH t1 AS
(
SELECT * FROM myTable
WHERE (...) -- Should limit result to 1 row
),
t2 AS
(
SELECT col1 FROM t1
UNION ALL
SELECT col2 FROM t1
UNION ALL
(...)
)
SELECT AVG(col1) FROM t2;
这将显示您拥有的每个ID的所有字段的平均值。
SELECT AVG(125Hz+250Hz+500Hz+750Hz+1000Hz+1500Hz+2000Hz+3000Hz+4000Hz+6000Hz+8000Hz)
AS Average FROM table
GROUP BY ID
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