[英]Count number of NULL values in each column in SQL
我正在尝试编写一个脚本,该脚本将显示每列中的非空值的数量以及表中的总行数。
我找到了几种方法来做到这一点:
SELECT sum(case my_column when null then 1 else 0) "Null Values", sum(case my_column when null then 0 else 1) "Non-Null Values" FROM my_table;
和
SELECT count(*) FROM my_table WHERE my_column IS NULL UNION ALL SELECT count(*) FROM my_table WHERE my_column IS NOT NULL
但这些要求我手动输入每个列名。 有没有办法为每列执行此操作而不列出它们?
你应该使用execute
:
DECLARE @t nvarchar(max)
SET @t = N'SELECT '
SELECT @t = @t + 'sum(case when ' + c.name + ' is null then 1 else 0 end) "Null Values for ' + c.name + '",
sum(case when ' + c.name + ' is null then 0 else 1 end) "Non-Null Values for ' + c.name + '",'
FROM sys.columns c
WHERE c.object_id = object_id('my_table');
SET @t = SUBSTRING(@t, 1, LEN(@t) - 1) + ' FROM my_table;'
EXEC sp_executesql @t
可能是这样的
select count(case when Column1 is null then 1 end) as Column1NullCount,
count(case when Column2 is null then 1 end) as Column2NullCount,
count(case when Column3 is null then 1 end) as Column3NullCount
...
from My_Table
正如保罗所说,但这是一个例子:
DECLARE @TableName VARCHAR(512) = 'invoiceTbl';
DECLARE @SQL VARCHAR(1024);
WITH SQLText AS (
SELECT
ROW_NUMBER() OVER (ORDER BY c.Name) AS RowNum,
'SELECT ''' + c.name + ''', SUM(CASE WHEN ' + c.Name + ' IS NULL THEN 1 ELSE 0 END) AS NullValues FROM ' + @TableName AS SQLRow
FROM
sys.tables t
INNER JOIN sys.columns c ON c.object_id = t.object_id
WHERE
t.name = @TableName),
Recur AS (
SELECT
RowNum,
CONVERT(VARCHAR(MAX), SQLRow) AS SQLRow
FROM
SQLText
WHERE
RowNum = 1
UNION ALL
SELECT
t.RowNum,
CONVERT(VARCHAR(MAX), r.SQLRow + ' UNION ALL ' + t.SQLRow)
FROM
SQLText t
INNER JOIN Recur r ON t.RowNum = r.RowNum + 1
)
SELECT @SQL = SQLRow FROM Recur WHERE RowNum = (SELECT MAX(RowNum) FROM Recur);
EXEC(@SQL);
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