ActionHero JS与猫鼬

Question

我正在使用ActionHero js和Mongoose创建一些其他API。 我将Mongoose代码放在了一个初始化器中，一切正常。 当我修改某些文件时，项目将自动重新编译，并返回以下错误：OverwriteModelError：

编译后无法覆盖User模型。

我应该如何编辑代码以避免此错误？ “使用严格”；

var mongoose   = require('mongoose');


exports.mongo = function(api, next) {

    mongoose.connect(api.config.mongo.host);

    var db = mongoose.connection;
    db.on('error', console.error.bind(console, 'connection error:'));
    db.once('open', function callback () {
        console.log('Connection opened');
    });

    var Schema = mongoose.Schema,
        Types = mongoose.Schema.Types;

    var userSchema = mongoose.Schema({
        createdAt: { type: Date, default: Date.now(), required: true},
        updatedAt: { type: Date, required: false},
        email: { type: String, required: true },
        name: { type: String, required: true },
        surname: { type: String, required: true },
        password: { type: String, required: true },
        roles: [],
        tokens: [{
            code: String,
            expiryDate: { type: Date, default: Date.now() + 30 }
        }]
    });


    var User = mongoose.model('User', userSchema);

    var postSchema = mongoose.Schema({
        createdAt: { type: Date, default: Date.now(), required: true},
        updatedAt: { type: Date, required: false},
        content: { type: String, required: true },
        votes: { type: [Types.ObjectId], ref: 'User' } ,
        coordinates: { type: [Number], index: { type: '2dsphere' }, required: true },
        creator: { type: Schema.Types.ObjectId, ref: 'User', required: true }
    });


    var Post = mongoose.model('Post', postSchema);

    api.mongo = {
        mongoose: mongoose,
        user: User,
        post: Post
    };

    next();
};

Answer 1

如果您处于developmentMode，则actionhero将重新加载所有初始化程序。 您应该将连接步骤包装在_start（）块中，而不是每次都在它们中串联运行。 这样，actionhero可以重新加载文件，而无需重新运行连接步骤。

http://actionherojs.com/docs/core/initializers.html