我在获取json ex时无法解析json数组

Question

我正在尝试使用以下代码解析Json Array 。

我的URL是http://166.62.17.208/json_preferencess.aspx

我收到以下错误：

Error parsing data org.json.JSONException: No value for id

我显示的result如下：

[{"items":[{"id":"11","Item_Id":"123","Item_Name":"Chicken Cream /* and the remaining objects of the array*/

我得到的jArray如下：

[{"questions":[{"q_id":"1","q_question":"How would you rate our Menu /* and the remaining objects of the array*/

我得到的jArray的长度为1，即使长度大于一。

我已经在下面发布了我的代码，请逐步指导我，因为我是json的新手。

    String result = null;
    InputStream is = null;
    try{
            HttpClient httpclient = new DefaultHttpClient();

            HttpPost httppost = new HttpPost("http://166.62.17.208/json_preferencess.aspx");

            HttpResponse response = httpclient.execute(httppost); 

            HttpEntity entity = response.getEntity();
            is = entity.getContent();

            Log.e("log_tag", "connection success "+"nameValuePairs");

    }
    catch(Exception e)
    {
            Log.e("log_tag", "Error in http connection "+e.toString());


    }
    try
    {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,HTTP.UTF_8),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) 
            {
                    sb.append(line + "\n");

            }
            is.close();

            result=sb.toString();
          Log.e("log_tag", "result "+result.toString());
    }
    catch(Exception e)
    {
           Log.e("log_tag", "Error converting result "+e.toString());


    }
    try
    {
        JSONArray jArray = new JSONArray(result);
        Log.w("Lenghsssssss",""+jArray);
          String s="",s1,s2,s3,s4,s5,s6,s7,s8,s9;
          Log.w("Lengh",""+jArray.length());
            for(int i=0;i<jArray.length();i++){


                JSONObject json_data = jArray.getJSONObject(i);

                  s=json_data.getString("id");

                   Log.e("taskid from server","s");

            }



    }
    catch(JSONException e)
    {
            Log.e("log_tag", "Error parsing data "+e.toString());

    }

Answer 1

[ // Json Array
    { // Json Object
        "items": [// Josn Array
            {
                "id": "11",

这样尝试

JSONArray jArray = new JSONArray(result);
        String s="",s1,s2,s3,s4,s5,s6,s7,s8,s9;
        Log.w("Lengh",""+jArray.length());
        for(int i=0;i<jArray.length();i++){
            JSONArray newarr = jArray.getJSONObject(i).getJSONArray("items");
            for(int j= 0; j<newarr.length();j++){
                JSONObject json_data = newarr.getJSONObject(i);
                s=json_data.getString("id");
                System.out.println("Id is: "+ s);
            }
        }