如何比较单个数字与另一个数组中的不同数字？ Java脚本

Question

我有一个ID（示例：2），我有一个列表，其中包含不同的ID（示例：1、2、3、4、5）。 我希望在列表中用1、2、3、4、5以及2是否相等（两个ID与2 = 2相同）来检查ID 2。 但是在我的代码中，它仅检查第一行。 因此，因为另一个数组以1而不是2开头，所以我的代码找不到连接并且不执行任何操作。 像这样：

        2 = 1 , false
(here it stops) = 2,  false
(here it stops) = 3,  false
(here it stops) = 4,  false

我想要这个：

        2 = 1 , false
        2 = 2 , true -> execute a code
        2 = 3 , false
        2 = 4 , false

有人可以帮我从这里出去吗 ？ 这是我的代码：

for (var i = 0; i < emailArray.length; i++) {

    if (ascalda[i].address_email.indexOf(emailArray[i].email_id) >= 0) {
        emaill.push(emailArray[i].email_title);
    }

数组：

ascalda: 

{"address_id":"1",
"address_street":"Vlietstraat",
"address_postalcode":"4536 DG",
"address_housenr":"1",
"address_city":"Terneuzen",
"address_country":"Nederland",
"address_email":"1",
"address_telnr":"1"};





emailArray:
 [
 {email_id: '2', email_title: 'RocWebmail@roc.nl', email_type: '9'},
 {email_id: '1', email_title: 'ScaldaWebmail@scalda.nl', email_type: '8'}
 ];

我使用钛作为程序。 提前致谢！！

我的控制台日志：

[INFO][ActivityManager(   62)] Starting: Intent { cmp=com.Innovisionsolutions.com/org.appcelerator.titanium.TiActivity (has extras) } from pid 425
[INFO][TiAPI   (  425)]  ["1"]
[INFO][TiAPI   (  425)]  [{"address_id":"1","address_street":"Vlietstraat","address_postalcode":"4536 DG","address_housenr":"1","address_city":"Terneuzen","address_country":"Nederland","address_email":"1","address_telnr":"1"}]
[INFO][TiAPI   (  425)]  1
[INFO][TiAPI   (  425)]  undefined
[INFO][TiAPI   (  425)]  [{"address_id":"1","address_street":"Vlietstraat","address_postalcode":"4536 DG","address_housenr":"1","address_city":"Terneuzen","address_country":"Nederland","address_email":"1","address_telnr":"1"}]
[INFO][TiAPI   (  425)]  [{"email_id":"2","email_title":"RocWebmail@roc.nl","email_type":"9"},{"email_id":"1","email_title":"ScaldaWebmail@scalda.nl","email_type":"8"}]
[INFO][TiAPI   (  425)]  1
[INFO][TiAPI   (  425)]  ["ScaldaWebmail@scalda.nl"]
[INFO][TiAPI   (  425)]  ["623232323"]
[INFO][ActivityManager(   62)] Displayed com.Innovisionsolutions.com/org.appcelerator.titanium.TiActivity: +1s248ms

Answer 1

你尝试过这个吗

    for (var j = 0; i < ascalda.length; j++) {
     for (var i = 0; i < emailArray.length; i++) {
        if (ascalda[j].address_email == emailArray[i].email_id) {
            emaill.push(emailArray[i].email_title);
        } 
     }
    }

由于两个值都使用相同的字符串（“ 1”，“ 2” ..）。