[英]Plugin Error - array_merge(): Argument #2 is not an array
我正在构建我的第一个wordpress插件,错误日志抛出以下错误。
[06-Jul-2014 20:07:21 UTC] PHP Warning: array_merge(): Argument #2 is not an array in \wp-content\plugins\test-plugin\screen.php on line 49
[06-Jul-2014 20:07:21 UTC] PHP Warning: array_merge(): Argument #2 is not an array in \wp-content\plugins\test-plugin\screen.php on line 50
[06-Jul-2014 20:07:21 UTC] PHP Warning: end() expects parameter 1 to be array, null given in \wp-content\plugins\test-plugin\screen.php on line 323
[06-Jul-2014 20:07:21 UTC] PHP Warning: Invalid argument supplied for foreach() in \wp-content\plugins\test-plugin\screen.php on line 324
对于第49和50行的错误,代码为:
function register_settings() {
global $menu;
global $submenu;
$this->menus = array_merge(array(), $menu);
$this->submenus = array_merge(array(), $submenu);
$this->settings = get_option( $this->settings_name );
register_setting( 'admin-theme', $this->settings_name );
}
对于第323和324行的错误,代码为:
function admin_menu() {
global $menu;
global $submenu;
// update menu
end( $menu );
foreach ($menu as $k=>&$v){
$id = explode(' <span', $v[0]);
$slug = 'menu_'.strtolower( str_replace( ' ','_',$id[0] ) );
$slug_hide = $slug.'_hide';
if($id[0] != NULL && $this->get_setting($slug) !== NULL){
$v[0] = $this->get_setting($slug). ( isset($id[1]) ? ' <span '.$id[1] : '' );
}
if( $this->get_setting($slug_hide) ){
unset($menu[$k]);
}
// update the submenu
if( isset($submenu[$v[2]]) ){
foreach ($submenu[$v[2]] as $key=>&$val){
$id = explode(' <span', $val[0]);
$slug_sub = $slug.'_'.strtolower( str_replace( ' ','_',$id[0] ) );
$slug_sub_hide = $slug_sub.'_hide';
if($id[0] != NULL && $this->get_setting($slug_sub) !== NULL){
$val[0] = $this->get_setting($slug_sub). ( isset($id[1]) ? ' <span '.$id[1] : '' );
}
if( $this->get_setting($slug_sub_hide) ){
unset( $submenu[$v[2]][$key] );
}
}
}
}
}
我似乎无法弄清楚,因此如果有人可以帮助或指出正确的方向,将不胜感激。
首先,您需要检查两个变量是否都是数组
使用is_array()
就像if(is_array($menu))
如果不使用类型强制转换来转换数组中的变量
if(is_array($menu))
$this->menus = array_merge(array(), $menu);
else
$this->menus = array_merge(array(), (array)$menu);
if(is_array($submenu))
$this->submenus = array_merge(array(), $submenu);
else
$this->submenus = array_merge(array(), (array)$submenu);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.