[英]Square brackets causing error in URL string in android
嗨,我在Android中执行URL时遇到问题,我确定它与方括号有关,但我找不到任何解决方案。 欢迎大家提出意见。
protected String doInBackground(String... arg0) {
try {
int indexdevice = 12;
String uuu = URLEncoder.encode ("http://<ipaddress>/ZWaveAPI/Run/devices[2].instances[0].commandClasses[0x25].Set(255)", "UTF-8");
HttpClient Client = new DefaultHttpClient();
String SetServerString = "";
HttpGet httpget = new HttpGet(uuu);
ResponseHandler<String> responseHandler = new BasicResponseHandler();
SetServerString = Client.execute(httpget,responseHandler);
Log.v("NAS", "--------- amount is " + SetServerString);
}
catch (Exception ex)
{
Log.v("NAS",String.valueOf(ex));
}
我得到的错误是:
07-08 12:37:33.970: V/NAS(1800): java.lang.IllegalStateException:
Target host must not be null, or set in parameters. scheme=null, host=null,
您使用url编码完整的url,包括http和主机名。 那行不通。 只需在主机地址后编码部分:
String uuu = "http://<ipaddress>/"+URLEncoder.encode ("ZWaveAPI/Run/devices[2].instances[0].commandClasses[0x25].Set(255)", "UTF-8");
http://可能正在编码,请尝试使用类似String foo = foo.replaceFirst(“ http://”,“”); foo =“ http://” + foo
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