[英]SQL Replace query to remove prefix from name contains (MR., MRS., MR / MRS…)
我有这样的内容表
tblEmployees
employeeID employeeName ___________________________________ 1 Jeffrey L. JR Van Hoosear 2 DAVID GUNGNER MR 3 CATHLEEN E STADECKER MRS. 4 MARTIN W SCHIFFMILLER 5 JAY F MOLDOVANYI VI
另一个像这样的桌子
tblPrefix
prefixID Prefix _________________________ 1 JR 2 MR 3 MR / MRS 4 JR. 5 MRS. 6 I 7 II 8 III 9 IV 10 V 11 VI 12 VII
现在我想删除EmployeeName中存在的前缀(JR,JR。,MR,MRS .....)。
我写了一个函数。 对于该功能,我已经将Employee名称作为参数传递给了
SELECT * FROM fn_SplitName (@employeeName) (Table-Valued Function)
我尝试过这样
SELECT REPLACE(@employeeName,preFix,'')
FROM tblPrefix
WHERE @employeeName LIKE '% ' + preFix + ' %'
预期输出
employeeID employeeName ___________________________________ 1 Jeffrey L. Van Hoosear 2 DAVID GUNGNER 3 CATHLEEN E STADECKER 4 MARTIN W SCHIFFMILLER 5 JAY F MOLDOVANYI
与第一个tblEmpoyee进行比较
Oracle查询:
select employeeName, REPLACE(employeeName, PREFIX,'')
from employee_table, prefix_table
WHERE INSTR(employeeName, PREFIX) > 0
在SQL Server中 ,我认为应该是:
select employeeName, REPLACE(employeeName, PREFIX,'')
from employee_table, prefix_table
WHERE CHARINDEX(PREFIX,employeeName) > 0
以下查询选择以前缀开头或结尾的employeeNames。 然后,使用SUBSTRING
函数将前缀删除employeeName。
编辑 :更正了CASE语句。
SELECT te.employeeName,
CASE
WHEN te.employeeName like '%'+' '+tp.Prefix THEN SUBSTRING(te.employeeName, 1, LEN(te.employeeName)-LEN(tp.Prefix)-1)
WHEN te.employeeName like tp.Prefix+' '+'%' THEN SUBSTRING(te.employeeName, LEN(tp.Prefix)+2, LEN(te.employeeName)-LEN(tp.Prefix)-1)
END employeeName_without_Prefix
FROM tblEmployees te
INNER JOIN tblPrefix tp ON te.employeeName like '%'+' '+tp.Prefix OR te.employeeName like tp.Prefix+' '+'%';
上面的查询不会无意中替换在employeeName中间出现的前缀字符。
您可以将SQL语句嵌入到函数中,如下所示。 但是,请注意,该函数的执行速度会较慢,因为它会针对每个employeeName逐一执行。
CREATE FUNCTION dbo.remove_prefix (@employeeName varchar(100))
RETURNS varchar(100)
AS
BEGIN
DECLARE @employeeName_without_Prefix varchar(100)
SELECT @employeeName_without_Prefix =
CASE
WHEN te.employeeName like '%'+' '+tp.Prefix THEN SUBSTRING(te.employeeName, 1, LEN(te.employeeName)-LEN(tp.Prefix)-1)
WHEN te.employeeName like tp.Prefix+' '+'%' THEN SUBSTRING(te.employeeName, LEN(tp.Prefix)+2, LEN(te.employeeName)-LEN(tp.Prefix)-1)
END employeeName_without_Prefix
FROM tblEmployees te
INNER JOIN tblPrefix tp ON te.employeeName like '%'+' '+tp.Prefix OR te.employeeName like tp.Prefix+' '+'%';
RETURN (@employeeName_without_Prefix);
END;
参考 :
您的查询也可以更改为:
SELECT REPLACE(@employeeName,preFix,'')
FROM tblPrefix
WHERE
(
@employeeName LIKE '% ' + preFix + ' %'
OR @employeeName LIKE '%' + preFix + ' %'
OR @employeeName LIKE '% ' + preFix + '%'
OR @employeeName LIKE '%' + preFix + '%'
);
在以下情况下,您需要处理可能出现名称的情况:
'(space)PREFIX(space)'
->名称之间由空格包围的前缀。
例如:Jeffrey L. JR Van Hoosear
'PREFIX(space)'
->名称以前缀开头,后跟空格,然后是名称
例如:JR Jeffrey
'(space)PREFIX'
->以空格和前缀结尾的名称
例如:Jeffrey JR
'PREFIX'
->没有空格
示例:JR
下列
| Jeffrey L. JR Van Hoosear |
| GEORGE WASHINGTON |
| MARTHA D CUSTIS |
| JOHN VON NEUMANN |
| ROBERT G MONDAVI |
不能解决“ JR”的原因是:
select
ca3.employeeName
from tblEmployees
cross apply (
select
charindex(' ',employeeName)
, charindex(' ',reverse(employeeName))
, len(employeeName)
) ca1 (posl, posr, wide)
cross apply (
select
case when posl > 1 then left(employeeName,posl-1) end
, case when posr > 1 then right(employeeName,posr-1) end
) ca2 (bitl, bitr)
cross apply (
select
case
when bitl in (select prefix from tblPrefix) then
substring(employeeName,posl+1,wide)
when bitr in (select prefix from tblPrefix) then
substring(employeeName,1,wide - posr)
else
employeeName
end
) ca3 (employeeName)
在“ MR / MRS”上也会失败
在您的函数中使用此查询。 IT将删除在开头,结尾和中间出现的前缀
SELECT REPLACE(@employeeName,preFix,'')
FROM tblPrefix
WHERE @employeeName LIKE '% ' + preFix + ' %'
OR @employeeName LIKE '% ' + preFix
OR @employeeName LIKE preFix + ' %'
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