[英]SQL users searching query
我想创建查询来搜索表users
给定信息。 该表包括: id
, username
, firstname
, lastname
, phone
和email
。
示例搜索文本: mat h 50 @ld
应该返回的唯一记录: 1 | admin | mat | hladeo | 123450789 | admin@localhost
1 | admin | mat | hladeo | 123450789 | admin@localhost
我的查询:
SELECT * FROM `users` WHERE (
(`firstname` LIKE '%mat%') || (`firstname` LIKE '%h%') ||
(`firstname` LIKE '%50%') || (`firstname` LIKE '%@l%') ||
(`firstname` LIKE '%d%')
) && (
(`lastname` LIKE '%mat%') || (`lastname` LIKE '%h%') ||
(`lastname` LIKE '%50%') || (`lastname` LIKE '%@l%') ||
(`lastname` LIKE '%d%')
) && (
(`phone` LIKE '%mat%') || (`phone` LIKE '%h%' ) ||
(`phone` LIKE '%50%') || (`phone` LIKE '%@l%') ||
(`phone` LIKE '%d%')
) && (
(`email` LIKE '%mat%') || (`email` LIKE '%h%') ||
(`email` LIKE '%50%' ) || (`email` LIKE '%@l%') ||
(`email` LIKE '%d%')
) && (
(`username` LIKE '%mat%') || (`username` LIKE '%h%') ||
(`username` LIKE '%50%') || (`username` LIKE '%@l%') ||
(`username` LIKE '%d%')
)
但是此查询返回的用户名包含d
且电话号码包含50
。
编辑:
该查询返回3行:
1 | admin | mat | hladeo | 123450789 | admin@localhost
8 | dillese | Adriana | Zolch | 44450232 | dilesse@msn.com
12 | dcolhut | Denise | Colhut | 502222222 | dcolhut@msn.com
并且应该仅返回第一行(因为匹配所有要求)。
==========
还有一个主要问题-如何优化此查询? 有可能使其更简单吗?
问候
我认为应该这样做:
SELECT * FROM `users` WHERE (
(firstname LIKE '%mat%' OR lastname LIKE '%mat%' OR
phone LIKE '%mat%' OR email LIKE '%mat%' OR username LIKE '%mat%')
AND
(firstname LIKE '%h%' OR lastname LIKE '%h%' OR
phone LIKE '%h%' OR email LIKE '%h%' OR username LIKE '%h%')
AND
(firstname LIKE '%50%' OR lastname LIKE '%50%' OR
phone LIKE '%50%' OR email LIKE '%50%' OR username LIKE '%50%')
AND
(firstname LIKE '%@l%' OR lastname LIKE '%@l%' OR
phone LIKE '%@l%' OR email LIKE '%@l%' OR username LIKE '%@l%')
AND
(firstname LIKE '%d%' OR lastname LIKE '%d%' OR
phone LIKE '%d%' OR email LIKE '%d%' OR username LIKE '%d%')
)
您需要分别测试每个条件,而不是每个字段。
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