[英]Oracle SQL - simplifying the totals column
我要解决以下问题:
以下是我的查询:
SELECT
status AS "ROW LABELS",
COUNT(case when source = 'INTERNET' THEN 1 end) AS "INTERNET",
COUNT(case when source = 'SALES' THEN 1 end) AS "SALES",
COUNT(case when source = 'REP' THEN 1 end) AS "REP",
COUNT(case when source = 'COM' THEN 1 end) AS "COM",
(COUNT(case when source = 'INTERNET' THEN 1 end) +
COUNT(case when source = 'SALES' THEN 1 end) +
COUNT(case when source = 'REP' THEN 1 end) +
COUNT(case when source = 'COM' THEN 1 end)
) AS Total
FROM
SOMETABLE
GROUP BY ROLLUP((status))
order by 1;
以下是我的数据:
如果用“简化”来表示“使计算更简洁”,则可以。 以下将起作用:
COUNT(CASE WHEN source IN ('INTERNET', 'SALES', 'REP', 'COM') THEN 1 END)
只需使用nvl
将NULL转换为值: NVL(status, 'TOTAL') AS row_labels
ROLLUP( (status) )
与ROLLUP( status )
相同
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