SQL Server-计算所有列中具有相同值的记录

Question

我完全不知道该怎么做。 我一直在绞尽脑汁，搜寻互联网，但我认为没有任何“简单”的解决方案。

当多个列中的值相同时，我希望能够计算给定userID的出现次数。 并非所有列都具有一条记录，但是我希望在计数中捕获的是所有不为null的所有具有相同值的记录。 我在下面提供了一个示例。

注意：我可以在SQL Server或Access中运行它。

Current Table:
CREATE TABLE INFO_TABLE 
    ([UID] int, [Question1] int, [Question2] int, [Question3] int, [Question4] int, [Question5] int)
;


INSERT INTO INFO_TABLE 
    ([UID], [Question1], [Question2], [Question3], [Question4], [Question5])
VALUES
    (100, 5, 5, 5, 5, 5),
    (100, 5, 5, 4, 4, 5),
    (100, 3, 5, 5, 5, 5),
    (200, 5, 5, 5, 5, 5),
    (200, , 1, 1, 1, 1),
    (100, 5, 5, 5, 5, 5),
    (300, 4, 4, 4, 4, 4),
    (400, 5, 5, 3, 3, 5),
    (400, 5, 5, 4, 5, 5),
    (300, 5, 5, 5, 5, );

所需结果：

CREATE TABLE INFO_TABLE 
    ([UID] int, [CountFlat] int)


INSERT INTO INFO_TABLE 
    ([UID], [CountFlat])
VALUES
    (100, 2),
    (200, 2),
    (300, 2),
    (400, 0);

Answer 1

您可以这样做：

select id, count(*)
from info_table
where coalesce(question1, question2, question3, question4, question5) = coalesce(question2, question3, question4, question5, question1) and
      coalesce(question1, question2, question3, question4, question5) = coalesce(question3, question4, question5, question1, question2) and
      coalesce(question1, question2, question3, question4, question5) = coalesce(question4, question5, question1, question2, question3) and
      coalesce(question1, question2, question3, question4, question5) = coalesce(question5, question1, question2, question3, question4)
group by id;

Answer 2

如果您先将数据标准化，

create table INFOTABLE_normalized
  ([UID] int, [QUESTION_SET_ID] int, [QUESTION_NUM] int, [QUESTION] int)

然后查询变成您原始问题的逐词重述：

with sets_with_only_one_distinct_question AS (
  select
    [UID]
   ,[QUESTION_SET_ID]
  from INFOTABLE_normalized
  where [QUESTION] is not NULL
  group by [UID],[QUESTION_SET_ID]
  having COUNT(DISTINCT [QUESTION]) = 1
)
select 
  [UID]
 ,COUNT([QUESTION_SET_ID]) AS [COUNT_FLAT]
from sets_with_only_one_distinct_question
group by [UID]