[英]JPA Inheritance with Two Abstract Class
我对JPA中的继承有疑问,是否可以使用JOINED策略执行此层次结构?
这是我的代码:
@Entity
@Table(name = "PERSON")
@Inheritance(strategy = InheritanceType.JOINED)
@DiscriminatorColumn(name = "DTYPE", discriminatorType = DiscriminatorType.STRING, length = 4)
public abstract class Person implements Serializable {
...
}
@Entity
@Table(name = "EMPLOYEE")
@DiscriminatorValue(value="EMPL")
public abstract class Employee extends Person implements Serializable{
...
}
@Entity
@Table(name="CLIENT")
@DiscriminatorValue(value="CLIE")
public class Client extends Person implements Serializable{
...
}
@Entity
@Table(name="TEACHER")
@DiscriminatorValue(value="TEAC")
public class Teacher extends Employee implements Serializable{
...
}
经过上面的层次结构后,我尝试使用JPQL进行查询,这是查询:
@Entity
@Table(name="FICHA_EVALUACION")
public class SheetEvaluation implements Serializable{
@OneToOne
private Teacher teacher;
}
该代码从主运行
Query query = entityManager.createQuery("SELECT f FROM SheetEvaluation f, Teacher teac, Employee emp, Person per WHERE f.teacher.id = teac.id and teac.id = emp.id and emp.id = per.id");
List<SheetEvaluation> sheetEvaluations = query.getResultList();
for (SheetEvaluation sheetEvaluation : sheetEvaluations ) {
System.out.println(" Teacher Name= " + sheetEvaluation .getTeacher().getName());
}
当我运行查询时,抛出以下错误
由以下原因引起:com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:“字段列表”中的未知列“ employee1_.DTYPE”
如果您对所获得的错误类型有任何了解,请多加支持。
最好的祝福
我不是冬眠大师,但是我认为在使用每个类的表时,您不能拥有@DiscriminatorColumn
,仅当您对所有插入的类拥有单个类并且想要区分它们时才需要。
看看这单表连接。
在您当前的联接中,它将为所有类创建表,并且将有个人fk。
@Entity
@Table(name = "PERSON")
@Inheritance(strategy = InheritanceType.JOINED)
public class Person implements Serializable {
...
}
@Entity
@Table(name = "EMPLOYEE")
public class Employee extends Person implements Serializable{
...
}
@Entity
@Table(name="CLIENT")
public class Client extends Person implements Serializable{
...
}
@Entity
@Table(name="TEACHER")
public class Teacher extends Employee implements Serializable{
...
}
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