[英]Android MediaPlayer Error -1004
我在使用MediaPlayer时遇到问题。 这在SherlockFragment
,当我使用XML创建按钮时就可以使用。
工作代码如下所示:
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.stop:
if(mPlayer!=null && mPlayer.isPlaying()){
mPlayer.stop();
buttonPlay.setText("Play");
mPlayer.reset();
buttonPlay.setEnabled(true);
}
break;
case R.id.play:
mPlayer.setAudioStreamType(AudioManager.STREAM_MUSIC);
buttonPlay.setEnabled(false);
buttonPlay.setText("Playing...");
try {
mPlayer.setDataSource(url);
} catch (IllegalArgumentException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 1", Toast.LENGTH_LONG).show();
} catch (SecurityException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 2", Toast.LENGTH_LONG).show();
} catch (IllegalStateException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 3", Toast.LENGTH_LONG).show();
} catch (IOException e) {
e.printStackTrace();
}
mPlayer.prepareAsync();
final ProgressDialog progressDialog;
progressDialog = ProgressDialog.show(getActivity(), "", "Fetching files...");
mPlayer.setOnPreparedListener(new OnPreparedListener() {
@Override
public void onPrepared(MediaPlayer mp) {
//Now dismis progress dialog, Media palyer will start playing
progressDialog.dismiss();
mp.start();
}
});
break;
}
}
它工作正常,但我需要它来以编程方式创建这样的按钮:
play[i].setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Log.e("button", "play clicked ");
mPlayer = new MediaPlayer();
mPlayer.setAudioStreamType(AudioManager.STREAM_MUSIC);
try {
mPlayer.setDataSource(url);
} catch (IllegalArgumentException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 1", Toast.LENGTH_LONG).show();
} catch (SecurityException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 2", Toast.LENGTH_LONG).show();
} catch (IllegalStateException e) {
Toast.makeText(getActivity(), "mPlayer.setDataSource(url); error 3", Toast.LENGTH_LONG).show();
} catch (IOException e) {
e.printStackTrace();
}
play[a].setText("Playing...");
for(int j =0; j < jsons.length; j++){
if(a != j ){
play[j].setEnabled(false);
stop[j].setEnabled(false);
Log.e("button", "making buttons false");
}
}
mPlayer.prepareAsync();
final ProgressDialog progressDialog;
progressDialog = ProgressDialog.show(getActivity(), "", "Fetching files...");
mPlayer.setOnPreparedListener(new OnPreparedListener() {
@Override
public void onPrepared(MediaPlayer mp) {
//Now dismis progress dialog, Media palyer will start playing
progressDialog.dismiss();
mp.start();
Log.e("button", "playing ");
}
});
}
});
stop[i].setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Log.e("button", "stop clicked ");
}
});
我得到这个:
E/MediaPlayer(8362): error (1, -1004)
E/MediaPlayer(8362): Error (1,-1004)
url = "http://******.******.ie/music/Mark%20Beswick%20-%20My%20Help.mp3";
请问我做错了什么?
顺便说一句,我正在4.1.1 Android上进行测试,这可能是问题吗?
这是解决方案:
<permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.INTERNET" />
<permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
感谢此问题的第一个答案- 播放SoundCloud Track
错误代码1004在某些设备中也使我感到困扰。 最后,我对URL进行了编码并解决了!
url = "http://******.******.ie/" + Uri.encode("music/Mark Beswick - My Help.mp3");
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