[英]Hibernate update a certain value
我已经编码了一种方法,如果它具有某个标识符,它将选择或更新一个值:
@Transactional
public List<Settings> getSettingsByParameter(String identifier) throws Exception {
log.info("get resultsList by " + identifier);
if(identifier.isEmpty()) {
throw new Exception("Identifier is empty!");
}
if(identifier == "today") {
//update today field
String query = "UPDATE settings SET value=TODAY() where identifier = '" + identifier + "'";
em.merge(em.createQuery(query, Settings.class).getSingleResult());
}
String query = "SELECT p FROM Settings p WHERE identifier = '" + identifier + "'";
List<Settings> resultList = em.createQuery(query, Settings.class).getResultList();
return resultList;
}
但是,我得到一个例外:
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: settings is not mapped [UPDATE settings SET value=TODAY() where identifier = 'today']
为什么以及使用hibernate和hsqldb怎么可能?
非常感谢您的回答!
Hibernate对类名区分大小写。 尝试使用Captial S来访问Settings类:
String query = "UPDATE Settings SET value=TODAY() where identifier = '" + identifier + "'";
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