从另一个多维数组向多维数组添加键

Question

我已经看到了很多有关添加到多维数组的信息，但是我不知道它们如何应用于我的情况。 我试图以一个大型多维数组结束。

我有一个从会员数据库的mysql查询中编译的多维关联数组。 我所有的数组都是使用while循环编译的。

Array(
     [0] => Array ( [full_name] => Amy Smith [id] => 00111111 [member_ref] => 1 [type] => 1 ) 
     [1] => Array ( [full_name] => Bob Smith [id] => 00222222 [member_ref] => 2 [type] => 0 ) 
     [2] => Array ( [full_name] => Cam Smith [id] => 00333333 [member_ref] => 3 [type] => 2 ) 
     )

这是从mysql_query编译的

SELECT full_name, id, member_ref, type 
FROM members 
ORDER BY full_name asc

然后，我在另一张表中为已支付会员资格的人提供了[id]号列表。 这是由另一个组织提供的。 这将成为[付费]密钥。

Array(
      [0] => Array ( [id] => 00111111 ) 
      [1] => Array ( [id] => 00333333 ) 
      [2] => Array ( [id] => 00444444 ) 
     )

来自查询：

SELECT * FROM paid

最后是一个表，该表将在指定时间范围内的成员出席情况计数为[log]键。

Array(
 [0] => Array ( [member_ref] => 1 [COUNT(member_ref)] => 17 ) 
 [1] => Array ( [member_ref] => 2 [COUNT(member_ref)] => 10 ) 
 [2] => Array ( [member_ref] => 3 [COUNT(member_ref)] => 1 )
     )

从

SELECT member_ref, COUNT(member_ref) 
FROM log 
WHERE timestamp >= STR_TO_DATE('$from') 
AND timestamp < STR_TO_DATE('$to') 
GROUP BY member_ref

我要结束的是：（请注意，鲍勃·史密斯尚未付款）

 Array(
     [0] => Array ( [full_name] => Amy Smith [id] => 00111111 [member_ref] => 1 [type] => 1 [paid] => 00111111 [log] => 17) 
     [1] => Array ( [full_name] => Bob Smith [id] => 00222222 [member_ref] => 2 [type] => 0 [paid] => 0 [log] => 10) 
     [2] => Array ( [full_name] => Cam Smith [id] => 00333333 [member_ref] => 3 [type] => 2 [paid] => 00333333 [log] => 1) 
      )

然后可以根据需要输出它，但是可以按任意键对数据进行排序。

我愿意使用单个mysql查询来执行此操作，其中的排序键是php $ var，但我无法弄清JOIN元素，这对我来说太复杂了。

谢谢

Answer 1

我的mySQL有点生锈，但是我认为这基本上是您想要的。 1次查询绝对有可能

SELECT m.full_name, m.id, m.member_ref, m.type, COUNT(l.member_ref) log,
Case WHEN p.Id != null
 THEN true
 ELSE false paid
FROM members m
LEFT JOIN paid p 
ON m.id = p.id
LEFT JOIN log l
ON m.member_ref = l.member_ref
WHERE l.timestamp >= STR_TO_DATE('$from') 
AND l.timestamp < STR_TO_DATE('$to')
ORDER BY m.full_name asc

Answer 2

从NSjonas的答案来看：

   SELECT m.full_name,
          m.id,
          m.member_ref,
          m.type, 
          (p.id IS NOT NULL) paid,
          COUNT(l.member_ref) log
     FROM members m
LEFT JOIN paid p
       ON m.id = p.id
LEFT JOIN log l
       ON m.member_ref = l.member_ref
      AND l.timestamp >= '$from' 
      AND l.timestamp < '$to'
 GROUP BY m.full_name, m.id, m.member_ref, m.type, p.id
 ORDER BY m.full_name ASC