[英]Unable to build Hibernate SessionFactory in Spring Boot
[英]Spring Boot - Handle to Hibernate SessionFactory
有谁知道如何获得由 Spring Boot 创建的 Hibernate SessionFactory 的句柄?
您可以通过以下方式完成此操作:
SessionFactory sessionFactory =
entityManagerFactory.unwrap(SessionFactory.class);
其中 entityManagerFactory 是 JPA EntityManagerFactory
。
package net.andreaskluth.hibernatesample;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
@Component
public class SomeService {
private SessionFactory hibernateFactory;
@Autowired
public SomeService(EntityManagerFactory factory) {
if(factory.unwrap(SessionFactory.class) == null){
throw new NullPointerException("factory is not a hibernate factory");
}
this.hibernateFactory = factory.unwrap(SessionFactory.class);
}
}
自动装配您的 Hibernate SessionFactory 的最简单和最不冗长的方法是:
这是 Spring Boot 1.x with Hibernate 4 的解决方案:
应用程序属性:
spring.jpa.properties.hibernate.current_session_context_class=
org.springframework.orm.hibernate4.SpringSessionContext
配置类:
@Bean
public HibernateJpaSessionFactoryBean sessionFactory() {
return new HibernateJpaSessionFactoryBean();
}
然后你可以像往常一样在你的服务中自动装配SessionFactory
:
@Autowired
private SessionFactory sessionFactory;
从带有 Hibernate 5 的 Spring Boot 1.5 开始,这是现在的首选方式:
应用程序属性:
spring.jpa.properties.hibernate.current_session_context_class=
org.springframework.orm.hibernate5.SpringSessionContext
配置类:
@EnableAutoConfiguration
...
...
@Bean
public HibernateJpaSessionFactoryBean sessionFactory(EntityManagerFactory emf) {
HibernateJpaSessionFactoryBean fact = new HibernateJpaSessionFactoryBean();
fact.setEntityManagerFactory(emf);
return fact;
}
伟大的工作安德烈亚斯。 我创建了一个 bean 版本,以便 SessionFactory 可以自动装配。
import javax.persistence.EntityManagerFactory;
import org.hibernate.SessionFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
....
@Autowired
private EntityManagerFactory entityManagerFactory;
@Bean
public SessionFactory getSessionFactory() {
if (entityManagerFactory.unwrap(SessionFactory.class) == null) {
throw new NullPointerException("factory is not a hibernate factory");
}
return entityManagerFactory.unwrap(SessionFactory.class);
}
它适用于 Spring Boot 2.1.0 和 Hibernate 5
@PersistenceContext
private EntityManager entityManager;
然后你可以使用 entityManager.unwrap(Session.class) 创建新的 Session
Session session = null;
if (entityManager == null
|| (session = entityManager.unwrap(Session.class)) == null) {
throw new NullPointerException();
}
示例创建查询:
session.createQuery("FROM Student");
应用程序属性:
spring.datasource.driver-class-name=oracle.jdbc.driver.OracleDriver
spring.datasource.url=jdbc:oracle:thin:@localhost:1521:db11g
spring.datasource.username=admin
spring.datasource.password=admin
spring.jpa.show-sql=true spring.jpa.hibernate.ddl-auto=create-drop
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.Oracle10gDialect
另一种类似于yglodt的方式
在 application.properties 中:
spring.jpa.properties.hibernate.current_session_context_class=org.springframework.orm.hibernate4.SpringSessionContext
在您的配置类中:
@Bean
public SessionFactory sessionFactory(HibernateEntityManagerFactory hemf) {
return hemf.getSessionFactory();
}
然后你可以像往常一样在你的服务中自动装配 SessionFactory:
@Autowired
private SessionFactory sessionFactory;
如果确实需要通过@Autowire 访问 SessionFactory,我宁愿配置另一个 EntityManagerFactory,然后使用它来配置 SessionFactory bean,如下所示:
@Configuration
public class SessionFactoryConfig {
@Autowired
DataSource dataSource;
@Autowired
JpaVendorAdapter jpaVendorAdapter;
@Bean
@Primary
public EntityManagerFactory entityManagerFactory() {
LocalContainerEntityManagerFactoryBean emf = new LocalContainerEntityManagerFactoryBean();
emf.setDataSource(dataSource);
emf.setJpaVendorAdapter(jpaVendorAdapter);
emf.setPackagesToScan("com.hibernateLearning");
emf.setPersistenceUnitName("default");
emf.afterPropertiesSet();
return emf.getObject();
}
@Bean
public SessionFactory setSessionFactory(EntityManagerFactory entityManagerFactory) {
return entityManagerFactory.unwrap(SessionFactory.class);
} }
SessionFactory sessionFactory = entityManagerFactory.unwrap(SessionFactory.class);
其中entityManagerFactory
是 JPA EntityManagerFactory
。
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