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[英]Spring MVC and Spring WS dispatcher servlet configuration in one web application
[英]Spring MVC dispatcher servlet, URIs without the application name
我正在尝试联系我的控制器:
package com.atmWebApp.controllers;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class FirstController {
@RequestMapping("/welcome/")
public ModelAndView helloWorld() {
String message = "<br><div align='center'>" + "<h1>Hello World, Spring 3.2.1 Example by Crunchify.com<h1> <br>";
message += "<a href='http://crunchify.com/category/java-web-development-tutorial/'>More Examples</a>";
return new ModelAndView("welcome", "message", message);
}
@RequestMapping("/")
public ModelAndView helloWorld1() {
String message = "<br><div align='center'>" + "<h1>Hello World, Spring 3.2.1 Example by Crunchify.com<h1> <br>";
message += "<a href='http://crunchify.com/category/java-web-development-tutorial/'>More Examples</a>";
return new ModelAndView("welcome", "message", message);
}
}
app-servlet.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan
base-package="com.atmWebApp.controllers" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>AtmWebApp</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>app</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app><?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>AtmWebApp</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>app</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
具体来说,我想启动我的服务器,并让我的根目录位于localhost:8080 /,但我什至看不到FirstController。 所以我的主要问题是:为什么我不点击FirstController中的任何一个方法?
我相信我的问题出在app-server.xml或web.xml文件中。 我在这里 , 这里 , 这里和这里浏览了堆栈溢出,但是我在做什么方面与这些人不同。
有什么帮助吗?
据我了解,您还应该在Controller上有一个@RequestMapping(..)
。 因此,您应该具有以下内容:
@Controller
@RequestMapping("/")
public class FirstController {
...
您也可以检查此响应的URL映射。
在web.xml文件的servlet映射下,尝试将Url-Pattern从/更改为/ *。
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