WFS Openlayers中的featureId过滤

Question

我想为wfs图层定义一个featureId拟合器，如下所示：

wfs = new OpenLayers.Layer.Vector("WFS Vectore", {
        strategies: [new OpenLayers.Strategy.BBOX(), saveStrategy],
        projection: new OpenLayers.Projection("EPSG:4326"),
        protocol: new OpenLayers.Protocol.WFS({
            version: "1.1.0",
            srsName: "EPSG:4326",
            url: "http://localhost:8080/geoserver/iran/wms?service=WFS",
            featureType: "population",
            featureNS: "http://iran.kadaster.org",
            geometryName: "the_geom"
        }),
        filter:
            new OpenLayers.Filter.FeatureId({
                fids: ['population.913', 'population.912']
                //type: ?????
            })

    });

我不知道在过滤选项中设置什么“类型”变量？

Answer 1

过滤器类型FeatureId上没有'type'属性。

API文件

这就够了。

filter:new OpenLayers.Filter.FeatureId({
                fids: ['population.913', 'population.912'];

            });

Answer 2

问题被设置为fids字段。 当您将fids设置为['population.913', 'population.912'] ，这意味着它的fids等于'population.913'和'population.912' 。 如果将fids字段设置为'population.912'或'population.913'则会得到正确的响应