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[英]Finding last entity of a joined entity in entityRepository (Symfony2 & Doctrine2)
[英]symfony2 doctrine count number of joined entity
我有与manyToOne关系的文章和类别实体。 我想列出带有文章数的类别。 如何使用Doctrine2进行有效查询?
如果您已经正确设置了类别实体,那么只需调用其getter计数就可以获取其文章集合,假设您具有如下映射的实体
文章
class Article
{
// ...
/**
* @ORM\ManyToOne(targetEntity="Category", inversedBy="articles")
* @ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
protected $category;
// ... title ,id ,bla bla bla
}
类别
use Doctrine\Common\Collections\ArrayCollection;
class Category
{
// ...
/**
* @ORM\OneToMany(targetEntity="Article", mappedBy="category")
*/
protected $articles;
// ... title ,id ,bla bla bla
public function __construct()
{
$this->articles= new ArrayCollection();
}
}
然后,您可以在控制器中循环类别实体
$DM = $this->getContainer()->getDoctrine()->getManager();
$categories = $DM->getRepository('Namespace\YourBundle\Entity\Category')->findAll();
foreach($categories as $c){
echo $this->getTitle();
echo count($this->getArticles());
}
在树枝上
{% for c in categories %}
{{ c.getTitle() }}
{{ c.getArticles()|length }}
{% endfor %}
通过查询生成器,您可以这样做
$DM = $this->getContainer()->getDoctrine()->getManager();
$query = $DM->createQueryBuilder()
->select('c.id,c.title, COUNT(a.id) as article_count')
->from('NamespaceYourBunle:Category', 'c')
->innerJoin('c.articles', 'a')
->groupBy('c.id')
;
$categories= $query->getQuery()->getResult();
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