我的MySQLi查询给出了错误，但我找不到那是错的

Question

我正在使用mysql查询来使用LEFT OUTER JOIN从多个表中选择数据。 现在当我执行查询时出现以下错误：

您的SQL语法有误； 检查与您的MySQL服务器版本对应的手册以获取正确的语法，以在第16行的'wg.werkbon_global_id = wk.werkbon_klant_globalid左外部加入用户AS u'附近使用

唯一的问题是我找不到我的查询出了什么问题。

PHP查询：

$query = '
    SELECT
        wg.werkbon_global_id AS id,
        wg.werkbon_global_status AS status,
        wg.werkbon_global_date_lastedit AS date,
        usr.user_firstname AS monteur_vn,
        usr.user_insertion AS monteur_tv,
        usr.user_lastname AS monteur_an,
        wg.werkbon_global_type AS type,
        wg.werkbon_global_layout AS layout,
        wg.werkbon_global_werkzaamheden AS werkzaamheden,
        wg.werkbon_global_opmerkingen AS opmerkingen,
        wk.werkbon_klant_nummer AS klantnr
    FROM
        werkbon_klant AS wk
    LEFT OUTER JOIN werkbon_global AS wg
        wg.werkbon_global_id = wk.werkbon_klant_globalid
    LEFT OUTER JOIN users AS usr
        usr.user_id = wg.werkbon_global_monteur_finish
    WHERE
        wk.werkbon_klant_nummer = '.$db->Quote($klantid).'
    ORDER BY id ASC;
$result = $db->loadAssoc($query);

我认为我的问题与左外部连接有关，但又如何呢？

Answer 1

您在联接中缺少ON运算符！

联接的正确语法是：

SELECT * FROM x LEFT JOIN y ON condition WHERE...

Answer 2

 $query = "
 SELECT
    wg.werkbon_global_id AS id,
    wg.werkbon_global_status AS status,
    wg.werkbon_global_date_lastedit AS date,
    usr.user_firstname AS monteur_vn,
    usr.user_insertion AS monteur_tv,
    usr.user_lastname AS monteur_an,
    wg.werkbon_global_type AS type,
    wg.werkbon_global_layout AS layout,
    wg.werkbon_global_werkzaamheden AS werkzaamheden,
    wg.werkbon_global_opmerkingen AS opmerkingen,
    wk.werkbon_klant_nummer AS klantnr
FROM
    werkbon_klant AS wk
LEFT OUTER JOIN werkbon_global AS wg
    wg.werkbon_global_id = wk.werkbon_klant_globalid
LEFT OUTER JOIN users AS usr
    usr.user_id = wg.werkbon_global_monteur_finish
WHERE
    wk.werkbon_klant_nummer = '.$db->Quote($klantid).'
ORDER BY id ASC";

$ result = $ db-> loadAssoc（$ query）;

确保没有缺少报价

Answer 3

由于arkascha解决了问题

现在，固定查询为：

$query = '
    SELECT
        wg.werkbon_global_id AS id,
        wg.werkbon_global_status AS status,
        wg.werkbon_global_date_lastedit AS date,
        usr.user_firstname AS monteur_vn,
        usr.user_insertion AS monteur_tv,
        usr.user_lastname AS monteur_an,
        wg.werkbon_global_type AS type,
        wg.werkbon_global_layout AS layout,
        wg.werkbon_global_werkzaamheden AS werkzaamheden,
        wg.werkbon_global_opmerkingen AS opmerkingen,
        wk.werkbon_klant_nummer AS klantnr
    FROM
        werkbon_klant AS wk
    LEFT OUTER JOIN werkbon_global AS wg ON
        wg.werkbon_global_id = wk.werkbon_klant_globalid
    LEFT OUTER JOIN users AS usr ON
        usr.user_id = wg.werkbon_global_monteur_finish
    WHERE
        wk.werkbon_klant_nummer = '.$db->Quote($klantid).'
    ORDER BY id ASC';
$result = $db->loadAssoc($query);

@fred我不需要按列名添加引号。 您只需要按字符串/ blob值添加引号。 @johny我的$ db-> Quote（）函数将自动添加qoutes。 我不需要添加它们并将所有内容都放在引号中。

谢谢大家的帮助。