不兼容的类型 struct* 和 struct，

Question

感谢您花时间阅读我的问题，我查看了一些类似的问题，它们在这种情况下似乎没有帮助，尽管可能会帮助其他遇到类似问题的人：

C：不兼容的类型？
结构为 C 中不兼容的指针类型
结构 C 的不兼容类型错误

我正在尝试在 c (-std=c99) 中创建一个简单的链表结构，此时我的结构相当通用：

typedef struct
{
  int count;
  char* word;
  struct node *nextNode;
}node;

然后在一个函数中，我有一个“根”或“头”节点：

node *root;
root = (node *) malloc(sizeof(node));

我尝试稍后在函数中将节点分配给node nextNode ，如下所示：

if(root->nextNode == 0)
{
  root->nextNode = foo;
}

这导致错误：
“从类型node分配到类型struct node*时，错误不兼容类型
&foo不会改善这种情况，而是导致lvalue required as unary样式错误。

这是围绕我的问题的上下文：

    #include <stdio.h>
    #include <malloc.h>
    #include <string.h>

    typedef struct
    {
        int count;
        char* word;
        struct node *nextNode;
    }node;

    node makenode(char *word)
    {
        node x;
        x.word = word;
        x.count = 1;
        return x;
    }

    void processInput(int threshold, const char* filename)
    {   
        node *root;
        root = (node *) malloc(sizeof(node)); 
        root->nextNode = 0;  
        char* word;
        while(fgets(word, 29, stdin) != NULL){
            if(root->nextNode == 0)
            {
                root->nextNode = makenode(word);
            }

Answer 1

问题

    typedef struct             // make an alias for a structure with no tag name
    {
        int count;
        char* word;
        struct node *nextNode; // with a pointer to struct node (which does not exit)
    }node;                     // name the alias node

解决方案

    typedef struct node        // make an alias for a structure with tag name node
    {
        int count;
        char* word;
        struct node *nextNode; // with a pointer to struct node (which is this one)
    }node;                     // name the alias node

Answer 2

试试这个代码

     #include <stdio.h>
    #include <malloc.h>
    #include <string.h>

    typedef struct node //should give a name for this 
    {
        int count;
        char* word;
        struct node *nextNode;
    }node;

    static node *makenode(char *word) //start with static and returning type is node* because we are storing this output in root->nextNode which is *node pointer
    {
        node x;
        x.word = word;
        x.count = 1;
        return x;
    }

    void processInput(int threshold, const char* filename)
    {   
        node *root;
        root = (node *) malloc(sizeof(node)); 
        root->nextNode = NULL;  //pointer values should initialised to NULL not 0
        char* word;
        while(fgets(word, 29, stdin) != NULL){
            if(root->nextNode == NULL) ////pointer values should initialised to NULL not 0
            {
                root->nextNode = makenode(word);
            }
}