PHP的MySQL查询多个条件

Question

我需要mysql查询以获取其nid> 910 for user_id = 1和nid> 902 for used_id <> 1的项目。

有人这样做吗？ 搜索，但找不到它，因为我是php和mysql的新手。

Answer 1

您不能在WHERE条件中使用OR ：

SELECT *
FROM YourTable
WHERE (nid > 910 AND user_id = 1)
    OR (nid > 902 AND user_id <> 1)

Answer 2

尝试使用以下查询：

SELECT * FROM items WHERE (nid>910 AND user_id=1) OR (nid>902 and user_id!=1)

Answer 3

SQL查询：

SELECT * FROM table_name WHERE (nid>910 AND user_id=1) OR (nid>902 and user_id!=1);

但是，如果要从PHP调用它，则需要这样的东西：

<?php
$username = "your_name";
$password = "your_password";
$hostname = "localhost"; 
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
  or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";
//select a database to work with
$selected = mysql_select_db("exampledb",$dbhandle)
  or die("Could not select exampledb");
//execute the SQL query and return records
$result = mysql_query("SELECT * FROM table_name WHERE (nid>910 AND user_id=1) OR (nid>902 and user_id!=1);");
//fetch tha data from the database
while ($row = mysql_fetch_array($result)) {
   echo "ID:".$row{'user_id'}." Nid:".$row{'nid'}."<br />";
}
?>