从android调用wcf服务POST

Question

我的网址是http://example.com/WcfService/MasterService.svc

方法名称为“ SearchOrganizations”；

字符串url = URL1 +“ /” + METHOD_NAME_SEARCH_ORGANIZATION +“ /”;

因此我的网址将是http://example.com/WcfService/MasterService.svc/SearchOrganizations/

服务类型为POST。 这是我的代码，可以从android调用此服务

JSONObject jsonObjSend = new JSONObject();
        try {
            jsonObjSend.put("data", params[0]);
            jsonObjSend.put("CurrentUserId", params[1]);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        List<NameValuePair> paramswithkey = new ArrayList<NameValuePair>();
        paramswithkey.add(new BasicNameValuePair("data", params[0]));
        paramswithkey
                .add(new BasicNameValuePair("CurrentUserId", params[1]));
        HttpClient client = new DefaultHttpClient();
        HttpPost httpPostRequest = new HttpPost(url);

        // httpPostRequest.setHeader("Accept", "application/soap+xml");
        httpPostRequest.setHeader("Content-Type",
                "application/x-www-form-urlencoded; charset=utf-8");
        UrlEncodedFormEntity se = null;
        try {
            // se = new StringEntity(jsonObjSend.toString());
            se = new UrlEncodedFormEntity(/*
                                         * jsonObjSend.toString().getBytes(
                                         * "UTF8")
                                         */paramswithkey);
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        httpPostRequest.setEntity(se);
        HttpResponse response = null;
        try {
            response = client.execute(httpPostRequest);
        } catch (ClientProtocolException e) {
            Toast.makeText(getApplicationContext(),
                    "Please check your internet connection",
                    Toast.LENGTH_SHORT).show();
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        logI("BEFOR response METHOD_NAME_SEARCH_ORGANIZATION :" + response);
        BasicResponseHandler responseHandler = new BasicResponseHandler();
        String strResponse = null;
        if (response != null) {
            try {
                strResponse = responseHandler.handleResponse(response);
            } catch (HttpResponseException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        logI("AFTER response METHOD_NAME_SEARCH_ORGANIZATION :"
                + strResponse);

我已经使用了JsonObject和NameValuePair的这段代码，但是我得到了以下异常

 org.apache.http.client.HttpResponseException: Cannot process the message because the content type 'application/x-www-form-urlencoded; charset=utf-8' was not the expected type 'text/xml; charset=utf-8'.

.Net方面，他们使用x-www-form-urlencoded调用了服务，但我得到的预期类型应该是text / xml； 字符集= utf-8的

我如何设法致电POST服务。 我尝试了不同的方式来调用此服务，但未能获得响应

http://lukencode.com/2010/04/27/calling-web-services-in-android-using-httpclient/

但我无法得到回应。

Answer 1

尝试使用下面的代码片段，在WCF情况下它可以正常工作。 将名称值对中的参数传递给方法，您将从方法中获得字符串响应。 是的，请在测试此片段之前检查所有权限，因为您需要添加intetn

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("username", name));

public static String postRequest(String url, List<NameValuePair> nameValuePairs) {
        String getServerPath = Utils.SERVER_ADDRESS + "methodname";
        String result = null;

        try {
            Log.e("TAG", "url:: " + url);
            JSONObject jsonObject = new JSONObject();

            for (NameValuePair nvp : nameValuePairs) {
                String name = nvp.getName();
                String value = nvp.getValue();
                jsonObject.accumulate(name, value);
                Log.e("TAG", name + "=" + value);
            }
            HttpClient HC = new DefaultHttpClient();
            HttpPost post = new HttpPost(url);
            StringEntity se = new StringEntity(jsonObject.toString());
            se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
            post.setEntity(se);
            HttpResponse res = HC.execute(post);
            HttpEntity entity = res.getEntity();
            result = EntityUtils.toString(entity);
            Log.e("TAG", "result:: " + result);
            return result;
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        }

    }

Answer 2

我的代码也可以正常工作，但是从Webservice端收到的网址存在问题。

http://example.com/WcfService/MasterService.svc/web/SearchOrganizations/

感谢您帮助我user1621629 ...