使用扫描仪和文本文件在一行中获取特定字符串

Question

因此，我想让扫描仪分析文本文件的每一行，并在x个单词之后停止，在这种情况下，x = 3。

我的代码看起来像这样：

    scannerName.nextLine();
    scannerName.next();
    scannerName.next();
    scannerName.next();

好吧，这里的问题是nextLine（）使扫描程序越过当前行AS WELL AS返回字符串。 因此，如果我调用next（），它将只找到下一行的下一个字符串（对吗？）。

有什么方法可以满足我的要求吗？

谢谢

Answer 1

请尝试以下代码：-while（scannerName.hasNext（）！= null）{

scannerName.next(); //Returns the 1st word in the line
scannerName.next(); //Returns the 2nd word in the line
scannerName.next(); //Returns the 3rd word in the line
//Analyze the word.
scannerName.nextLine();

}

Answer 2

您的问题不是那么精确，但是我有一个从txt文件读取的解决方案：

Scanner scan = null;
    try {
        scan = new Scanner(new File("fileName.txt"));                       
    } catch (FileNotFoundException ex) {
        System.out.println("FileNotFoundException: " + ex.getMessage());
    } catch (Exception e) {
        System.out.println("Exception: " + e.getMessage());
    }

    int wordsRead = 0;
    int wordsToRead = 3;                               //== You can change this, to what you want...
    boolean keepReading = true;

    while (scan.hasNext() && keepReading) {
        String currentString = scan.nextLine();        //== Save the entire line in a String-object 
        for (String word : currentString.split(" ")) {
            System.out.println(word);                  //== Iterates over every single word - ACCESS TO EVERY WORD HAPPENS HERE
            wordsRead++;
            if (wordsRead == wordsToRead) {
                keepReading = false;                   //== makes sure the while-loop will stop looping
                break;                                 //== breaks when your predefined limit is is reached
            } //== if-end
        } //== for-end
    } //== while-end

有任何问题请告诉我:-)