[英]sql query + limit + count overall results in one query?
SELECT topics.*
FROM topics topics
JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
JOIN rh_topictags_tag t ON tt.tag_id = t.id
JOIN forums f ON f.forum_id = topics.forum_id
WHERE LOWER(t.tag) IN ('super', 'fun')
AND f.rh_topictags_enabled = 1
AND topics.forum_id IN (1, 2, 3, 4)
AND topics.topic_visibility = 1
GROUP BY topics.topic_id
HAVING count(t.id) = 2
ORDER BY topics.topic_last_post_time DESC
LIMIT 0, 10
我如何获得找到的总行数(没有限制)?
我不能使用SELECT FOUND_ROWS()
因为此查询必须在多个DBMS(mysql,mssql,oracle,postgres,sqlite,sqlite3)下运行。
不幸的是,这不起作用:
SELECT topics.*, COUNT(topics.*) AS result_count
FROM topics topics
JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
JOIN rh_topictags_tag t ON tt.tag_id = t.id
JOIN forums f ON f.forum_id = topics.forum_id
WHERE LOWER(t.tag) IN ('super', 'fun')
AND f.rh_topictags_enabled = 1
AND topics.forum_id IN (1, 2, 3, 4)
AND topics.topic_visibility = 1
GROUP BY topics.topic_id
HAVING count(t.id) = 2
ORDER BY topics.topic_last_post_time DESC
LIMIT 0, 10
那这个呢:
Select *
from
(
SELECT topics.*, count(*) as result_count
FROM topics topics
JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
JOIN rh_topictags_tag t ON tt.tag_id = t.id
JOIN forums f ON f.forum_id = topics.forum_id
WHERE LOWER(t.tag) IN ('super', 'fun')
AND f.rh_topictags_enabled = 1
AND topics.forum_id IN (1, 2, 3, 4)
AND topics.topic_visibility = 1
GROUP BY topics.topic_id
HAVING count(t.id) = 2
) a
ORDER BY a.topic_last_post_time DESC
LIMIT 0, 10
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