用IN选择会产生错误的结果

Question

现场编辑者将value '3,2,4'

sql语句

SELECT * FROM `table` where '3' in (editors)

结果1行=正确

SELECT * FROM `table` where '2' in (editors)

结果0行=不正确。

我假设value '3,2,4'被当作​​一个字符串，如何解决呢？

Answer 1

您必须使用FIND_IN_SET()或类似的可怕构造

  WHERE editors='2' 
    OR editors LIKE '2,%'
    OR editors LIKE '%,2,%'
    OR editors LIKE '%,2'

现在，您的查询被解释为

 WHERE '2' IN ('1,2,3')
 a.k.a
 WHERE '2' = '1,2,3'

并不是

 WHERE '2' IN ('1', '2', '3')
 a.k.a.
 WHERE '2' = '1' OR '2' = '2' OR '2' = '3'

就像你想要的那样。 哪里