[英]MySQL How to use dynamic PHP variables inside INSERT INTO SELECT query?
[英]insert with a select statement and php variables in 1 MySQL query
我有类似的东西可以将数据从表单插入到我的MySQL表中。 我在插入中使用select语句是否有效? 请赐教。
if(isset($_POST['date']) && isset($_POST['docName']) && isset($_POST['docSpec']) && isset($_POST['time']) && isset($_POST['symptoms']) )
{
$nameOfUser = $_COOKIE['userlogin'];
$docName = $_POST['docName'];
$date = $_POST['date'];
$symptoms = $_POST['symptoms'];
$time = date('H:i:s',strtotime($_POST['time']));
$id = mt_rand(1000,9999); //generate random appointment id
$insertQuery = "insert into appointment values
($id,(select doctorid from doctors where doctorName like '$docName' ),
$date,$symptoms,
(select patientid from patient where patientFName like '$nameOfUser'), $time)";
if(mysqli_query($conn,$insertQuery)===true)
{
echo "<script>alert('success');</script>";
}
else
{
die('Invalid query: ' . mysql_error());
$message .= 'Whole query: ' . $query;
die($message);
}
}
它说无效查询。 insert语句中的列已经按正确的顺序排列。 谁能帮我?
您必须指定要插入的列-
insert into appointment (col1, col2, col3, ...) values
($id,(select doctorid from doctors where doctorName like '$docName' ), $date,$symptoms,(select patientid from patient where patientFName like '$nameOfUser'),$time)";
看起来您有6列。
编辑:这种语法可能有助于清除问题-
$insertQuery = "INSERT INTO `appointment` (`col1`, `col2`, `col3`,`col4`,`col5`,`col6`) ";
$insertQuery .= "VALUES (";
$insertQuery .= "'" . $id . "'";
$insertQuery .= ", '" . "(SELECT `doctorid` FROM `doctors` WHERE `doctorName` LIKE '%" . $docName . "%')" . "'";
$insertQuery .= ", '" . $date . "'";
$insertQuery .= ", '" . $symptoms . "'";
$insertQuery .= ", '" . "(SELECT `patientid` FROM `patient` WHERE `patientName` LIKE '%" . $nameOfUser . "%')" . "'";
$insertQuery .= ", '" . $time . "'";
$insertQuery .= ")";
由于没有使用通配符,因此您还在使用LIKE而没有机会找到其他元素。
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